Answer:
The magnitude of the induced Emf is 
Explanation:
The width of the truck is given as 79inch but we need to convert to meter for consistency, then
The width= 79inch × 0.0254=2.0066 metres.
Now we can calculate the induced Emf using expresion below;
Then the 
Where B= magnetic field component
L= width
V= velocity
=(40*10^-6) × (42) × (2.0066)
=0.003371V
Therefore, the magnitude emf that is induced between the driver and passenger sides of the truck is 0.003371V
Answer:
A force is a push or pull that acts upon an object as a result of that objects interactions
Explanation:
Answer:
60 N
Explanation:
We can answer the question by using Newton's third law, which states that:
"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"
In this situation, we can identify the rope as object A, and the block as object B.
We are told that the rope exerts a force of 60 N on the block: if we apply Newton's third law, therefore, we can say that the block will also exert an equal (60 N) and opposite (in direction) force on the rope.
The distance covered by car is equal to (assuming it is moving by uniform motion) the product between the car's speed and the time of the car ride, 4 h:
where
is the car's speed
is the duration of the car ride
Similarly, the distance covered by train is equal to the product between the train's speed and the duration of the train ride, 7 h:
The total distance covered is S=255 km, which is the sum of the distances covered by car and train:
which becomes
(1)
we also know that the train speed is 5 km/h greater than the car's speed:
(2)
If we put (2) into (1), we find
and if we solve it, we find
So, the car speed is 20 km/h and the train speed is 25 km/h.
Answer: negative
Explanation: it may seem that neutrons would be negative but neutrons are neutral, protons are positive, and electrons are negative
