Answer:
<em>The ball falls 0.3 m in the first 1/4 seconds, and it falls 0.92 m in the second 1/4 second</em>
Explanation:
<u>Horizontal Launch </u>
When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.
To calculate the vertical distance (y) traveled by the object in terms of the time (t) we use:
The fastball is thrown horizontally. The distance the ball falls in t=1/4 seconds = 0.25 seconds, is:
The distance the ball falls in t=1/2 seconds = 0.5 seconds is:
The distance it falls in the second 1/4 second is:
The ball falls 0.3 m in the first 1/4 seconds, and it falls 0.92 m in the second 1/4 second