Answer:
The absolute zero temperature T = - 269.91° C
Explanation:
From the given information:
The plot of the volume of the experimental data against the celsius temperature can be expressed mathematically as:
V = mT + c
V = 0.0741 × T+c --- (1)
where;
m, which is the straight line of the slope = 0.0741
replacing the value of V to be = 20 L, T= 0.
Then:
20 = 0.0741 × 0 + c
20 = c
From equation (1), replacing the value of c with 20, we have:
V = 0.0741 × T+20
SO, to determine absolute zero temperature: we have the volume to be zero at absolute zero temperature, Thus:
0 = 0.0741 × T+20
0.0741 T + 20 = 0
0.0741 T = - 20
T = - 269.91° C
Answer:
D
Explanation:
A reaction that is exothermic and causes a decrease in the entropy of the system cannot be a spontaneous reaction. This is not totally true because naturally For a spontaneous process, the entropy of the universe (system plus surroundings) must increase. This is the 2nd law of thermodynamics. The system entropy can decrease as long as the entropy of the surroundings increases enough to make the sum of the system and surroundings positive.
And we know that a spontaneous reaction is a reaction that occurs in a given set of conditions without intervention. Spontaneous reactions are accompanied by an increase in overall entropy or disorder. If the Gibbs Free Energy is negative, then the reaction is spontaneous, and if it is positive, then it is nonspontaneous.
<span>The region(s) of the periodic table which are
made up of elements that can adopt both positive and negative oxidation numbers
are the “non-metal” region. As we can see on the periodic table, the elements situated
at the right side of the table have two oxidation states, one positive and the
other a negative. </span>
0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.
<h3>HOW TO CALCULATE NUMBER OF MOLES?</h3>
The number of moles of a substance can be calculated using the following expression:
PV = nRT
Where;
- p = pressure (atm)
- v = volume (L)
- n = number of moles
- R = gas law constant
- T = temperature
0.75 × 11.2 = n × 0.0821 × 300
8.4 = 24.63n
n = 8.4 ÷ 24.63
n = 0.34 moles
Therefore, 0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.
Learn more about number of moles at: brainly.com/question/1190311
Answer:
B : 0.133 M
Explanation:
moles Li3N3 = 0.4 mol Li x (2 moles Li3N/6 moles Li) = 0.133 M
