Answer:
Drag force=1/2Cd*Area*density*V^2
A=240 ft^2
cd=0.75
Drage force=675 lbs
<u>Answer</u>
3 Ohms
<u>Explanation</u>
when the resistors are in series, the resistance in the circuit increases. For example, if two resistors, R1 and R2 are in series, the combined resistance is R1+R2.
When connected in parallel, the total resistance is the reciprocal of (1/R1 + 1/R2)
In this case the resistors are in parallel.
Total resistance = (1/12 + 1/4)⁻¹
= (1/3)⁻¹
= 3 Ohms
Answer:
1)49m/s
2)122.5m
Explanation:
The expression below can be use to calculate the initial velocity from law of motion
V2 - V1= at
Where V2= final velocity
V1= initial velocity( from rest)
a=acceleration
t= time= 5 seconds
But V2=0
V1=gt
Where g= acceleration due to gravity= 9.8m/s^2
V1= 9.8×5
V1=49m/s
Then we can now calculate the maximum height the rocket reaches by using below formula
V^2=2gh
h(max)=v^2/2g
Where h= maximum height
V2= initial velocity
=49^2/(2×9.8)
=2401/19.6
=122.5m
Hence the maximum height it reaches vis 122.5m
Answer: First shot
Explanation:
A) Distance of puck from goal during the first shot = 5m away
Speed of puck during first shot = 10m/s
Time taken to score = ?
Since speed is the distance covered per unit time
i.e speed = Distance / time taken
Time taken = Distance / Speed
Time taken = 5m / 10m/s
= 0.5 seconds
B) Distance of puck from goal during the second shot = 10m away
Speed of puck during second shot = 40m/s
Time taken to score = ?
Recall that time taken = (Distance / Speed)
Time taken = 10m / 40m/s
= 0.25 seconds
It will take 0.5 seconds for the first shot to score whereas it will takes 0.25 seconds for the second shot to score.
Thus, the goalie have a better chance of blocking the first shot since it is slower than the second.
α=30°
F=20 N
Fh=F*cos(α)
Fv=F*cos(90-α)=F*sin(α) (vertical component of the force F)
Fv=20*0,5=10.00 N
Answer (C)