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Anastaziya [24]
3 years ago
11

Un avión vuela hacia al norte a una velocidad de 90 m/s, pero un fuerte viento sopla hacia al este a 20 m/s y desvía su rumbo. R

ealiza los trazos y encuentra el vector resultante.
Physics
1 answer:
vladimir2022 [97]3 years ago
7 0

La adicion de vectores permite encontrar la repuesta para la velocidad resultante del avión es:

  • Modulo de la veloicdad  v= 92,2 m/s
  • Dirección de esta veloicdad 12,5º al Norte del Este  

Las magnitudes vectoriales son cantidades tienen modulo y dirección, la velocidad es una de estas magnitudes, por lo tanto deben ser sumada usando álgebra vectorial.

Un sistema de referencia es un sistema desde donde realizar las mediciones, en este caso indican que usemos un sistema de los puntos cardinales.

En el adjunto podemos ver un esquema de los vectores velocidad y su resultante, realicemos el calculo de la resultante por método analíticos

Indican que el valor de la velocidad hacia el Este es vₓ = 20 m/s y la velocidad hacia el Norte es v_y = 90 m/s, por lo tanto, para la magnitud usamos el Teorema de Pitágoras

           R= \sqrt{v_x^2 + v_y^2}

           R = \sqrt{20^2 + 90^2}

          R = 92,2 m/s

Para encontrar la direccion usemos trigonometría

          tan θ = \frac{v_y}{v_x}

          θ = tan⁻¹ \frac{v_y}{v_x}

          θ = tan⁻¹ 20/90

          θ = 12,5º

La dirección se lee 12,5º al Norte del Este

En conclusión usando la suma de vectores  podemos encontrar la repuesta para la velocidad resultante del avión es:

  • v= 92,2 m/s  con dirección 12,5º al Norte del Este  

Aprender mas aquí:

brainly.com/question/21639180

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Answer:

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b) vf = 26.4 m/s

Explanation:

Given that;

m = 1400.0 kg

a)

by using the energy conservation

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mg × ( 3200-2800) = 1/2 ×m×v²

so

1400 × 9.8 × 400 = 0.5 × 1400 × v²

5488000 = 700v²

v² = 5488000 / 700

v² = 7840

v = √7840

v = 88.54 m/s

b)

Work done by all forces is equal to change in KE

W_gravity + W_non - conservative = 1/2×m×(vf² - vi²)

we substitute

1400 × 9.8 × ( 3200-2800) - (5 × 10⁶) = 1/2 × 1400 × (vf²  -0 )

488000 = 700 vf²

vf² = 488000 / 700

vf² = 697.1428

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The purpose of this lab is to explore the various ways to calculate projectile velocity using horizontal, vertical and angle inf
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Answer: A projectile is any object in which the only force is gravity

Explanation: Equations on how to calculate projectile velocity is stated below:

The initial velocity Vo being a vector quantity, has two componentsVox and Voy  

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V0y = V0 sin(θ) 

The acceleration A is a also a vector with two components Axand Ay given

Ax = 0 and Ay = - g = - 9.8 m/s2 

Along the x axis the acceleration is equal to 0 and therefore the velocity Vx is constant  

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Along the x axis the velocity Vx is constant and therefore the component x of the displacement is

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The interior space of large box is kept at 30 C. The walls of the box are 3 m high and have a ‘sandwich’ construction consisting
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Answer:

\frac{\dot Q}{A} =20.129\ W.m^{-2}

T_1=27.58\ ^{\circ}C & T_2=2.41875\ ^{\circ}C

Explanation:

Given:

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  • height of the walls of box, h=3\ m
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<u>From the Fourier's law of conduction:</u>

\dot Q=\frac{dT}{(\frac{x}{kA}) }

\dot Q=\frac{dT}{R_{th} } ....................................(1)

<u>Now calculating the equivalent thermal resistance for conductivity using electrical analogy:</u>

R_{th}=R_p+R_s+R_p

R_{th}=\frac{x_p}{k_p.A}+\frac{x_s}{k_s.A}+\frac{x_p}{k_p.A}

R_{th}=\frac{1}{A} (\frac{x_p}{k_p}+\frac{x_s}{k_s}+\frac{x_p}{k_p})

R_{th}=\frac{1}{A} (\frac{0.0125}{0.104}+\frac{0.05}{0.04}+\frac{0.0125}{0.104})

R_{th}=\frac{1.4904}{A} .....................(2)

Putting the value from (2) into (1):

\dot Q=\frac{30-0}{\frac{1.4904}{A} }

\dot Q=\frac{30\ A}{1.4904}

\frac{\dot Q}{A} =20.129\ W.m^{-2} is the heat per unit area of the wall.

The heat flux remains constant because the area is constant.

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\frac{\dot Q}{A} =k_p.\frac{T_i-T_1}{x_p}

20.129=0.104\times \frac{30-T_1}{0.0125}

T_1=27.58\ ^{\circ}C

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\frac{\dot Q}{A} =k_s.\frac{T_1-T_2}{x_s}

20.129=0.04\times \frac{27.58-T_2}{0.05}

T_2=2.41875\ ^{\circ}C

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