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Taya2010 [7]
3 years ago
10

Which formula can be used to find the show angle of the resultant vector? A)sin∅=Ry/Rx,B)tan∅=Rx/Ry, C)tan∅=Ry/Rx, D)sin∅=Rx/Ry

Physics
2 answers:
BartSMP [9]3 years ago
8 0

Answer:

Option (c)

Explanation:

There are six trigonometric ratios.

Sin theta, Cos theta, tan theta, cot theta, sec theta and cosec theta.

In a right angled triangle

Sin theta = perpendicular/hypotenuse

Cos theta= base / hypotenuse

Tan theta = perpendicular/ base

Cot theta = base/ perpendicular

Sec theta = hypotenuse/ base

Cosec theta= hypotenuse/ perpendicular

So, tan theta = Ry / Rx

aleksklad [387]3 years ago
4 0
The correct answer would be o/=Ry,B)tan because when you plug in all the other formula you would get a centered dipped like a shell shape
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A train accelerates at -1.5 m/s2 for 10 seconds. If the train had an initial
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Answer:

17 m/s

Explanation:

Using formula a = (v-u) /t

acceleration a =  -1.5 m/s2

final velocity v = unknown

initial velocity u = 32 m/s

time t = 10s

-1.5 = (v-32)/10

-15 = v - 32

-15 + 32 = v

v = 17 m/s

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3 years ago
What characteristics distinguish the inner planets in the solar system from the outer planets?
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  • The four inner plants have shorter orbits slower spin ,no rings ,and they are made up of rock and metal
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Explanation:

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5 0
2 years ago
If two charged objects in a laboratory are brought to a distance of 0.22 meters away from each other. What is
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Answer:

q_2=2.47\times 10^{-4}\ C

Explanation:

The charge on one object, q_1=9.9\times 10^{-5}\ C

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Let q₂ is the charge on the other sphere. The electrostatic force between two charges is given by the formula as follows :

F=\dfrac{kq_1q_2}{r^2}\\\\q_2=\dfrac{Fr^2}{kq_1}\\\\q_2=\dfrac{4550\times (0.22) ^2}{9\times 10^9\times 9.9\times 10^{-5}}\\\\q_2=2.47\times 10^{-4}\ C

So, the charge on the other sphere is 2.47\times 10^{-4}\ C.

7 0
3 years ago
A seagull flies at a velocity of 9.00 m/s straight into the wind. (a) if it takes the bird 20.0 min to travel 6.00 km relative t
enot [183]

Here we will the speed of seagull which is v = 9 m/s

this is the speed of seagull when there is no effect of wind on it

now in part a)

if effect of wind is in opposite direction then it travels 6 km in 20 min

so the average speed is given by the ratio of total distance and total time

v_{avg} = \frac{6000}{20*60}

v_{avg} = 5m/s

now since effect of wind is in opposite direction then we can say

V_{net} = v_{bird} - v_{wind}

5 = 9 - v_{wind}

v_{wind}= 4 m/s

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now if bird travels in the same direction of wind then we will have

v_{net}= v_{bird} + v_{wind}

v_{net} = 9 + 4 = 13 m/s

now we can find the time to go back

time = \frac{distance}{speed}

time = \frac{6000}{13}

time = 7.7 minutes

Part c)

Total time of round trip when wind is present

T = t_1 + t_2

T = 20 + 7.7 = 27.7 min

now when there is no wind total time is given by

T = \frac{6000}{9} + \frac{6000}{9}

T = 22.22 min

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4 0
3 years ago
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Answer:

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