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Taya2010 [7]
4 years ago
10

Which formula can be used to find the show angle of the resultant vector? A)sin∅=Ry/Rx,B)tan∅=Rx/Ry, C)tan∅=Ry/Rx, D)sin∅=Rx/Ry

Physics
2 answers:
BartSMP [9]4 years ago
8 0

Answer:

Option (c)

Explanation:

There are six trigonometric ratios.

Sin theta, Cos theta, tan theta, cot theta, sec theta and cosec theta.

In a right angled triangle

Sin theta = perpendicular/hypotenuse

Cos theta= base / hypotenuse

Tan theta = perpendicular/ base

Cot theta = base/ perpendicular

Sec theta = hypotenuse/ base

Cosec theta= hypotenuse/ perpendicular

So, tan theta = Ry / Rx

aleksklad [387]4 years ago
4 0
The correct answer would be o/=Ry,B)tan because when you plug in all the other formula you would get a centered dipped like a shell shape
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A sample of oxygen gas with a volume of 3.0 m3 is at 100 C. The gas is heated so that
vesna_86 [32]

\qquad\qquad\huge\underline{{\sf Answer}}

According to Charles law, if pressure remains constant, volume varies directly with temperature. so we can infer that :

\qquad\sf{\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}}

So, we can use this formula to find out the final temperature of the gas ~

Note : Take temperature in Kelvin ( 100°C = 373 K )

\qquad \sf  \dashrightarrow \:  \dfrac{3}{373}  =  \dfrac{6}{x}

\qquad \sf  \dashrightarrow \: x =  \dfrac{6}{3} \times 373

\qquad \sf  \dashrightarrow \: x = 2 \times 373

\qquad \sf  \dashrightarrow \: x =74 6 \: K

Now, convert it to Celsius ~

i.e 746 - 273 = 473° C

So, the final temperature of the gas will be equal to 473° C

6 0
2 years ago
Each shot of the laser gun favored by Rosa the Closer, the intrepid vigilante of the lawless 22nd century, is powered by the dis
Alisiya [41]

Answer:

a) 4.94e9 J  b) 1.07e10 J

Explanation:

The electric potential energy stored in a capacitor, expressed in terms of the value of the capacitance C, and the voltage between its terminals V, is as follows:

U =\frac{1}{2}*C*V^{2}

a) For the original capacitor, we can find directly U as follows:

U =\frac{1}{2}*1.81F*(73.9e3)^{2} V2 = 4.94e9 J  

U = 4.94*10⁹ J

b) Prior to find the electric potential energy of the upgraded capacitor, we need to find out the value of the capacitance C of this capacitor, which is identical to the original, except that has a different dielectric constant.

As the capacitance is proportional to the dielectric constant, we can write the following proportion:

ε₂ / ε₁ = \frac{943}{435}= \frac{C2}{C1} =\frac{Cx}{1.81F}

Cx =\frac{1.81F*943}{435} = 3.92 F

Once calculated the new value of the capacitance, as V remains the same, we can find the electric potential energy for the upgraded capacitor as follows:

U =\frac{1}{2}*3.92F*(73.9e3)^{2} V2 = 1.07e10 J

⇒ U = 1.07*10¹⁰ J

8 0
3 years ago
A 2,200 kg railway freight car coasts at 3.6 m/s underneath a grain terminal, which dumps grain directly down into the freight c
suter [353]

Answer:

m_2=2554.83\ kg

Explanation:

Given that,

Mass of the car, m_1=2200\ kg

Initial speed of the car, u=3.6\ m/s

Final speed of the car, v=3.1\ m/s

To find,

The maximum mass of grain that it can accept.

Solution,

We know that according to the law of conservation of momentum, the initial momentum is equal to the final momentum.

m_1u=m_2v

m_2=\dfrac{m_1u}{v}

m_2=\dfrac{2200\times 3.6}{3.1}

m_2=2554.83\ kg

Therefore, the maximum mass of grain that it can accept is 2554.83 kg. Hence, this is the required solution.

7 0
3 years ago
What important attitudes do successful scientists possess?
olganol [36]
They would use the Scientific method
8 0
3 years ago
Read 2 more answers
Ohm's Law for electrical circuits is stated Vequals​RI, where V is a constant​ voltage, R is the resistance in ohms and I is the
Annette [7]

Answer:

The resistance interval is  R  =  1.8 \pm  0.037

Explanation:

From the question we are told that

     The voltage is  V  =  9 V

      The current is  I = 5 \pm 0.1

The maximum current would be  

       I_{max} = 5 + 0.1 =  5.1 \ A

The minimum current would be  

      I_{min} = 5 -  0.1 =  4.9 \ A

The maximum resistance is  

      R_max =  \frac{V}{I_{min}}

     R_max =  \frac{9}{4.9}

     R_max =  1.837 \Omega

The minimum resistance is  

      R_{min} =  \frac{V}{I_{max}}

    R_{min} =  \frac{9}{5.1}

    R_{min} = 1.765 \Omega

and  R  =  \frac{9}{5}  =  1.8 \Omega

The  interval R  lies is  

        R  =  1.8 \pm  0.037

4 0
3 years ago
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