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hichkok12 [17]
2 years ago
9

Unbalanced force acting on a body may not change the dimension and balanced forces many change the dimension. JUSTIFY. Please he

lp me..​
Physics
1 answer:
Rainbow [258]2 years ago
8 0

If the body is in motion, the force operating on it simply produces the motion; however, if the force acting on it is balanced, the body is in a static position and its shape is flexible.

<h3>What is force?</h3>

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is explained as the multiplication of mass and acceleration. Its unit is N.

It is the external agent which helps to change the shape and size of an object. Force is used to pushing and pull the object and sometimes changes the direction of motion.

The net force acting on an object is equal to the sum of all forces acting upon it.

F = F1 + F2 + F3

The force is found as;

F=ma

Where,

Force, F

Mass,m

Acceleration,a

Unbalanced forces operating on a body might not modify its dimension, but balanced forces might.

The unbalanced forces act on the body is helps to give the motion to the body and only one application of force can act on the object.

If there is motion in the body the force acting on the body causes only the motion but if the force acting on the body is balanced the body is in static condition and the shape of the body can change.

Hence the given statement is justified unbalanced force acting on a body may not change the dimension and balanced forces may change the dimension.

To learn more about the force refer to the link;

brainly.com/question/26115859#SPJ1

#SPJ1

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A-Caclcuate the potential energy of the ball at that height

Explanation:

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Acceleration due to gravity = 9.8 m/s².

Using the Formula,Potential Energy = mgh

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(b). Now, By the law of the conservation of the Energy, Total amount of the energy of the system remains constant.

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∴ Kinetic Energy = 980 J.

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Potassium ions (K+) move across a 7.0 -mm- thick cell membrane from the inside to the outside. The potential inside the cell is
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           U = qV

or,    \Delta U = q \times \Delta V

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(a) 3.44 x 10^-3 m^3/s

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