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Montano1993 [528]
3 years ago
8

The closer the charged particles, the... the electrostatic force.

Physics
1 answer:
Anna35 [415]3 years ago
4 0

Answer:

please give me brain list and follow

Explanation:

Therefore, if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value. If the charges come 10 times closer, the size of the force increases by a factor of 100. The size of the force is proportional to the value of each charge.

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A spring, having an unstretched length of 2ft, has one end attached to the 10lb ball. determine the angle ? of the spring if the
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The angle theta of the spring is 31 degrees. To solve for this, show the equation which is equal to the 10lb ball. With this, the unknown will be the angle. Then transpose/transfer the terms in order to isolate the variable for the angle. First solve for s, then solve for angle theta. You will come up with s = .5849 ft and angle theta = 31.2629 or 31 degrees. Hope this helps.
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Newton would agree that all objects on Earth exert a
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A soccer ball is traveling at a velocity of 50 m/s. The kinetic energy of the ball is 500 J. What is the mass of the soccer ball
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3 years ago
Read 2 more answers
You are given two infinite, parallel wires, each carrying current.The wires are separated by a distance, and the current in the
miv72 [106K]

Answer:

A. Attractive

B. ( μ₀I² ) / ( 2πd )

Explanation:

A. We know that currents in the same direction attract, and currents in the opposite direction repel, according to ampere's law. In this case the current in the two wires are flowing in the same direction, and hence the force between the two wires are attractive.

B. Suppose that two wires of length l_1 and l_2 both carry the current I in the same direction ( given ). In the presence of a magnetic field produced by wire 1, a force of magnitude m say, is experienced by wire 2. The magnitude of the magnetic field produced by wire 1 at distance say d, from it's axis, should thus be the following -

B_1 = μ₀I / 2πd

The force experienced by wire 2 should thus be -

F_2 = I( l_2 * B_1 )

= I * l_2 * B_1 * Sin( 90 )

= I * l_2 ( μ₀I / 2πd )

Therefore the force per unit length experienced by wire 2 toward wire 1 should be ...

( F_2 / l_2 ) = ( μ₀I² ) / ( 2πd ) ... which is our solution

3 0
3 years ago
Three astronauts outside a spaceship and that they decide to play catch. All the astronauts weigh the same on Earth and are equa
guajiro [1.7K]

Answer:

Well concluding there is no gravity their motions would be slow and lightweighted. Let's say they were playing on Earth it would approximately take around 5 to 6 minutes even less, so in space it will approximately take around 10 to 12 minutes may be more but this is just my opinion after using my calculator! Hope this helped!

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3 years ago
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