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Kryger [21]
3 years ago
10

While working on her science fair project Venus connected a battery to a circuit that contained a light bulb. Venus decided to c

hange the battery to a higher voltage, but she kept the same light bulb. What will happen to the current?
Physics
2 answers:
MakcuM [25]3 years ago
7 0
When Venus put in a different battery with higher voltage ... no matter
what other components were in the circuit ... the voltage across the
light bulb, and the current through it, both had to increase, and the
light bulb had to shine brighter than before.  
krok68 [10]3 years ago
5 0

The correct answer to the question is : Current increases.

EXPLANATION:

Before going to answer this question, first we have to understand Ohm's law.

From Ohm's law, we know that current flowing through a conductor is directly proportional to the potential difference maintained across the two ends of the conductor at constant temperature and pressure.

But, mathematically it is written as -

                  V ∝ I

               ⇒ V = IR

Here,  V is the potential across the two ends of the conductor.

           I is the current flowing through the conductor.

          R is the resistance of the wire.

As per the question, the voltage is increased.

Hence, the current flowing through the wire is increased.


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At 9:13AM a car is traveling at 35 miles per hour. Two minutes later, the car istraveling at 85 miles per hour. Prove that are s
andreyandreev [35.5K]

Answer:

There is at least one instant which instantaneous acceleration is equal to average acceleration. a = 1500\,\frac{km}{h^{2}}.

Explanation:

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According to the Rolle's Theorem, there is at least one instant t so that instantaneous acceleration equal to average acceleration for the analyzed interval. That is to say:

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If car is accelerating at constant rate, instantaneous acceleration coincides with average acceleration for all instant t. Then, instantaneous acceleration is:

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3 years ago
Please Someone Help me I Need Help ASAP PLEASE
dimaraw [331]
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Rocket-powered sleds are been used to test the responses of humans to acceleration. Starting from rest, one sled can reach a spe
Greeley [361]

Answer:cho  v₀ =0s  

α=Δv/Δt

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\frac{0-495}{2,16-1,78}

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2 years ago
Please help me solve all of them ( a, b, c and d ) thankiew !! <br> I’m also kind of in a rush
Sergio039 [100]

Answer:

a-

V= IR

9V = I ×( 12+6)

I = 9/ 18 A = 0.5 A

b

V=IR

240 = 6 A ×( 20 + R)

40 = 20 + R

R = 20 ohm

c

resultant resistance of the 2 parallel resistances= Ro

1/Ro = 1/ 5 + 1/ 20

1/Ro =( 20+5)/100

= 1/Ro = 1/4

Ro= 4 ohm

V=IR

V = 2A × ( 1+ 4 OHM)

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d

equivalent resistance = Ro

1/Ro = 1/(2+8) + 1/(5+5)

1/Ro = 1/10 +1/10

2/10 = 1/ Ro

Ro= 10/2 = 5 ohm

V = IR

12V = I × 5Ohm

I=2.4 A

6 0
2 years ago
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