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Rufina [12.5K]
3 years ago
7

One mole of the acid HCl requires how many moles of OH- for neutralization?

Chemistry
1 answer:
Sergeeva-Olga [200]3 years ago
5 0

Answer:

One mole of the hydrochloric acid requires one mole of hydroxide ions to be neutralized.

Explanation:

Hydrochloric acid is a very strong acid an it fully dissociates at all concentrations. The neutralization of hydrochloric acid is conventional and any inorganic base such as sodium hydroxide can be used. Having a one molar hydrochloric acid solution means that for each mole of hydrochloric acid produces one mole of protons requiring one mole of hydroxide hydroxide ions to neutralize.

This can be illustrated by the equation shown below.

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ether has a density of 0.736 g/cm^3 at 20 degrees C. what is the volume, in liters, of 225.0 grams of ether?
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D = m / V

0.736 = 225.0 / V

V = 225.0 / 0.736

V = 305.7 cm³
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3 years ago
List three things that rely on the Sun as the major source of energy​
valkas [14]

Answer:

Three things that rely on the sun for energy is coal,oil, and natural gases

Explanation:

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3 years ago
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What is relativity exactly
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3 years ago
Two substances, A and Z, are to be identified. Substance A can not be broken down by a chemical change. Substance Z can be broke
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Answer;

(3) Substance A is an element and substance Z is a compound.

Explanation;

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What volume of water is required to prepare 0.1 M H3PO4 from 100 ml of 0.5 M solution?
ExtremeBDS [4]

Answer: A volume of 500 mL water is required to prepare 0.1 M H_{3}PO_{4} from 100 ml of 0.5 M solution.

Explanation:

Given: M_{1} = 0.1 M,    V_{1} = ?

M_{2} = 0.5 M,       V_{2} = 100 mL

Formula used to calculate the volume of water is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\0.1 M \times V_{1} = 0.5 M \times 100 mL\\V_{1} = 500 mL

Thus, we can conclude that a volume of 500 mL water is required to prepare 0.1 M H_{3}PO_{4} from 100 ml of 0.5 M solution.

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3 years ago
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