How does the image distance and magnification give information about the type of image is produced bya lens or multiple lenses/
1 answer:
Explanation:
The image distance gives the position of image formed by a lens. It also shows how far the image is formed form the pole of the lens. There is a relationship between the object distance, object distance and the focal length of the lens. It is given by :
Where
v is the image distance
u is the object distance
f is the focal length of the lens
The ratio of image distance to the object distance is called the magnification of the lens. It is given by :
Magnification of lens is also defined as the ratio of the height of the image to the height of the object. It is given by :
h' is the height of image
h is the height of object
The magnification of a lens shows that how many times the image is magnified. If the magnification of a lens is more than 1, it shows that the image is greater than the object and if it is less than 1, it shows the image is smaller than the object.
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Answer:
New pressure of the gas increases by 26.5% with respect to initial pressure, new volume decreases 27% with respect to initial volume and new temperature decreases 8% with respect to initial volume.
Explanation:
If we assume the gas is a perfect gas we can use the perfect gas equation:
- For Isothermal process:
(1)
Where subscripts 1 shows before the isothermal process and 2 after it, because isothermal means constant temperature T1=T2, and pressure increases by 10% means P2=1,1*P1, using these facts on (1) we have:
(2)
- For Isobaric process:
(3)
Where subscripts 2 shows before the isobaric process and 3 after it, because isobaric means constant pressure P2=P3, and volume decreases by 20% means V3=0.8*V2, using these facts on (3) we have:
(4)
- For Isochoric process:
(5)
Where subscripts 3 shows before the isochoric process and 4 after it, because isochoric means constant volume V3=V4, and temperature increases by 15% means T4=1.15*T3, using these facts on (5) we have:
(6)
So now because P4=1.15*P3, P2=P3 and P2=1.1*P1:
This is, the new pressure of the gas increases by 26.5% with respect to initial pressure.
Similarly, we have V3=V4, V3=0.8*V2 and V1=1,1*V2:
so the final volume decreases 27% with respect to initial volume.
T4=1,15*T3, T3=0.8*T2 and T1=T2:
The new temperature decreases 8% with respect to initial volume.
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