How does the image distance and magnification give information about the type of image is produced bya lens or multiple lenses/
1 answer:
Explanation:
The image distance gives the position of image formed by a lens. It also shows how far the image is formed form the pole of the lens. There is a relationship between the object distance, object distance and the focal length of the lens. It is given by :
Where
v is the image distance
u is the object distance
f is the focal length of the lens
The ratio of image distance to the object distance is called the magnification of the lens. It is given by :
Magnification of lens is also defined as the ratio of the height of the image to the height of the object. It is given by :
h' is the height of image
h is the height of object
The magnification of a lens shows that how many times the image is magnified. If the magnification of a lens is more than 1, it shows that the image is greater than the object and if it is less than 1, it shows the image is smaller than the object.
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The component of the force in negative z-direction is -0.144 N.
The given parameters;
- <em>current in the wire, I = 2.7 A</em>
- <em>length of the wire, L = (3.2 i + 4.3j) cm</em>
- <em>magnetic filed, B = 1.24 i</em>
The force on the segment of the wire is calculated as follows;
where;
- <em>θ is the angle wire and magnetic field</em>
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The force on the wire segment will be perpendicular in negative z-direction (applying right hand rule), so there won't be any x and y component of the force.
The angle between the wire and the magnetic field is calculated as follows;
The magnitude of the wire length is calculated as follows;
The component of the force in negative z-direction is calculated as;
Thus, the component of the force in negative z-direction is -0.144 N.
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