Question

Question 1 of 10

Answer 1

• (-1,2) and (7,3)

Midpoint

• (-1+7/2,2+3/2
• (6/2,5/2)
• 3,5/2)

Answer 2

Answer:

$\textsf{C.} \quad \left(3,\dfrac{5}{2}\right)$

Step-by-step explanation:

Midpoint between two points

$\textsf{Midpoint}=\left(\dfrac{x_2+x_1}{2},\dfrac{y_2+y_1}{2}\right)\quad \textsf{where}\:(x_1,y_1)\:\textsf{and}\:(x_2,y_2)\:\textsf{are the endpoints}}\right)$

Define the endpoints of the line segment:

$\textsf{Let }(x_1,y_1)=(-1,2)$

$\textsf{Let }(x_2,y_2)=(7,3)$

Substitute the defined endpoints into the midpoint formula and solve:

$\implies \textsf{Midpoint}=\left(\dfrac{7+(-1)}{2},\dfrac{3+2}{2}\right)$

$\implies \textsf{Midpoint}=\left(3,\dfrac{5}{2}\right)$