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Yuki888 [10]
2 years ago
5

A ball is dropped from rest from the top of a high building. Ignore air resistance and take g = 9,8 m/s² calculate speed of the

ball after 1sec.
​
Physics
1 answer:
Alex2 years ago
3 0

The speed of the ball after one second is obtained as 9.8 m/s.

<h3>What is the speed after 1 second?</h3>

We know that  since the ball dropped from a height, its initial velocity is zero.

Thus we have;

u = 0 m/s

v = ???

g =  9,8 m/s²

t =  1sec

Given that;

v = u + at

v = at

v =  9,8 m/s² *  1sec

v = 9.8 m/s

Learn more about acceleration:brainly.com/question/12550364?

#SPJ1

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