Answer:
D
Explanation:
beacause all the elements in period 3 has different valence electrons hence you look at the first element in period 3 is sodium which has a valence electron of 1 when you go across the period to the right their valence electron decreases to be negative
Answer:
At the burner temp. and pressure, 18.85 litres of air is needed to completely combust each gram of propane
Explanation:
The combustion stoichiometry is as follows:
C₃H₈ + 5O₂ = 4 H₂O + 3CO₂ The molecular weights (g/mol) are:
MW 44 5x32 4x18 3x44
So each gram of propane is 1/44 = 0.02272 mol propane
and will need 5 x 0.02272 = 0.1136 mol oxygen
At 0.21 mol fraction oxygen in air, 0.1136 / 0.21 = 0.54 mol air is needed to burn the propane.
At the low pressure in the burner we can use the Ideal Gas Law
PV=nRT, or V = nRT/P
P = 1.1 x 101325 Pa = 111457 Pa
T = 195°C + 273 = 468 K
R = 8.314
and we calculated n = number of moles air = 0.54 mol
So V m³ = 0.54 x 8.314 x 468 / 111457 = 0.0188 m³ = 18.85 litres air.
Answer:
c. The reaction will proceed rapidly from left to right.
Explanation:
The variation of the free Gibbs energy doesn't tell anything about the speed of reaction.
On the other hand, when ΔGo is negative: the reaction is spontaneous, thermodynamically favourable, and the products are more stable than the reactants
A bond is a force of attraction between atoms. They are mainly fthree types of bonds namely; ionic bond, which involves transfer of electrons between a metal and a non metal, covalent bond which occurs between non metal atoms by sharing of electrons, metallic bond which is a bond in the metal structure between metal atoms and the sea of electrons. in this case carbon and hydrogen are non metals hence they will have a covalent bond between their atoms.
