Question

If 65.39 g of zinc are mixed with some unknown mass of hydrochloride acid, 136.29 g of zncl2 are formed along with 2.00 g of hydrogen gas. what mass of hydrochloric acid was used?

Answer 1

How much hydrogen chloride acid was used?

72.916 g of hydrochloric acid was used.

Given:

Mass of Zn = 65.39 g

Mass of $ZnCl_{2}$ =136.29 g

Mass of $H_{2}$ = 2 g

Equation:

The chemical equation for the reaction of zinc with hydrochloric acid:

Zn + 2HCl → Zn $Cl_{2}$ + $H_{2}$

Hydrogen gas is created when zinc combines with hydrochloric acid, which causes the process to bubble ferociously. Another sign that a chemical reaction is taking place is the generation of a gas.

Calculation:

A number of equivalents equate:

Number of equivalents = $\frac{given mass}{Molecular Mass}$ x 1000 x equivalent factor

$\frac{x}{36.458}$ x 1000 x 1 = $\frac{136.29}{136.286}$ x 1000 x 2

$x$ = 36.458 x 2

$x$ = 72.916

Learn more about the calculation of mass here,

brainly.com/question/21290034

#SPJ4