Question

A sample of neon gas has a volume of 752 mL at 298 Kelvin (K). What will be the volume at 373 K if

Answer 1

Answer:

V2 = 0.941 L

Explanation:

This follows the Charles' law, a gas law.

Using this eq $\frac{V1}{T1} =\frac{V2}{T2}$

From the given, the missing variable is V2

$\frac{752 ml}{298 K} =\frac{V2}{373 K}$, change ml to SI unit of Volume (L)

752 ml = 0.752 L

$\frac{752 L}{298 K} =\frac{V2}{373 K}$, then cross multiply

$280.496 L (K) =298K (V2)$

$\frac{280.496 L (K) }{298K} = (V2)$

$V2 = 0.941 L$