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luda_lava [24]
2 years ago
9

A sample of neon gas has a volume of 752 mL at 298 Kelvin (K). What will be the volume at 373 K if

Chemistry
1 answer:
Firdavs [7]2 years ago
8 0

Answer:

V2 = 0.941 L

Explanation:

This follows the Charles' law, a gas law.

Using this eq \frac{V1}{T1} =\frac{V2}{T2}

From the given, the missing variable is V2

\frac{752 ml}{298 K} =\frac{V2}{373 K}, change ml to SI unit of Volume (L)

752 ml = 0.752 L

\frac{752 L}{298 K} =\frac{V2}{373 K}, then cross multiply

280.496 L (K) =298K (V2)

\frac{280.496 L (K) }{298K} = (V2)

V2 = 0.941 L

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What is hydrogen bonding
yKpoI14uk [10]

Answer:

a weak bond between two molecules resulting from an electrostatic attraction between a proton in one molecule and an electronegative atom in the other.

Explanation:

For example, in water molecules (H2O), hydrogen is covalently bonded to the more electronegative oxygen atom. Therefore, hydrogen bonding arises in water molecules due to the dipole-dipole interactions between the hydrogen atom of one water molecule and the oxygen atom of another H2O molecule.

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3 years ago
A box contains identical balls of which 12 are red, 18 white and 8 blue. Three balls are drawn from the box one after the other
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Answer:

a) 12/323

b) 8/233

Explanation:

a) The probability of a red ball being drawn is 12/38, or in a simplified fraction, 6/19. To find the probability that 3 are red you would multiply the probability of the fraction for each, except subtracting one from the total each time as the drawn is done without replacement. This is done as follows: 6/19 × 6/18 × 6/17= 12/323

b) The probability of drawing a blue ball is 8/38, or 4/19. To find that the first one is blue and the rest are red, the equation is done as follows: 4/19 × 6/18 × 6/17 = 8/233

(hopefully I did this right)

8 0
3 years ago
2c+02=2CO2. The moles of co2 produced when 0.25 moles of O2 react is?​
Sophie [7]
<h3>Answer:</h3>

\displaystyle 0.5 \ mol \ CO_2

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Moles
  • Compounds

<u>Stoichiometry</u>

  • Using Dimensional Analysis
  • Analyzing Reactions RxN
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2C + O₂ → 2CO₂

[Given] 0.25 moles O₂

[Solve] moles CO₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol O₂ → 2 mol CO₂

<u>Step 3: Stoichiometry</u>

  1. [DA] Set up:                                                                                                     \displaystyle 0.25 \ moles \ O_2(\frac{2 \ mol \ CO_2}{1 \ mol \ O_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                        \displaystyle 0.5 \ mol \ CO_2
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2 years ago
crash course video about periodic table - The Periodic Table: Crash Course Chemistry #4 - write a reflection about this video
Stolb23 [73]

Answer:

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Explanation:

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3 years ago
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