Ask question

Ask question

All categories

3 years ago

14

If two children, with masses of 16 kg and 25 kg, sit in seats opposite one another in a rotating merry-go-round with an arm leng

th of 1.5 m from the origin, what is the moment of inertia about the rotation axis?

1 answer:

Jlenok [28]3 years ago

4 0

Answer:

$92.25 kgm^2$

Explanation:

Assume both children bodies are point particles. The total moment of inertia about the rotation axis of 2 points particles of mass 16 kg and 25 kg at 1.5 m arm length is

$\sum I = m_1r_1^2 + m_2r_2^2$

where $m_1 = 16 kg, m_2 = 25 kg$ are the masses of 2 children $r_1 = R-2 = 1.5m$ are their distance to the center of rotation

$\sum I = 16*1.5^2 + 25*1.5^2 = 1.5^2(16 + 25) = 92.25 kgm^2$

You might be interested in

A team of eight dogs pulls a sled with waxed wood runners on wet snow (mush!). The dogs have average masses of 18.5 kg, and the

meriva

Answer:

a. $2.86 m/s^2$

b.1058 N

Explanation:

We are given that

Mass of each dog,M=18.5 kg

Mass of sled with rider,m=250 kg

a.Average force,F=185 N

$\mu_s=0.14$

$g=9.8 m/s^2$

By Newton's second law

$8F-f=(8M+m)a$

$a=\frac{8F-f}{8M+m}=\frac{8(185)-(0.14)(9.8)(250)}{8(18.5)+250}$

$a=2.86 m/s^2$

b.By Newton's second law

$T=ma+\mu_s mg$

Substitute the values

$T=250\times 2.86+0.14(250)(9.8)=1058 N$

Hence, the force in the coupling between the dogs and the sled=1058 N

8 0

3 years ago

The crew of an enemy spacecraft attempts to escape from your spacecraft by moving away from you at 0.259 of the speed of light.

Vladimir79 [104]

If you do not have to use relative physics but classic physics, this is how you solve it:

Speed of light = c = 3 * 10^5 km/s

Speed of your foe respect to you: 0.259c

Speed of the torpedo respect to you: 0.349c

Speed of the torpedo respect your foe: 0.349c - 0.259c = 0.09c

Conversion to km/s = 0.09 * 3.0 * 10^5 km/s = 27000 km/s

Note that this solution, using classic physics do not take into account time and space dilation.

Answer: 27000 km/s

4 0

3 years ago

Guys please helpp!!!!1

Setler79 [48]

Answer:

Position A/Position E

$K = E$ , $U = 0$

Position B/Position D

$K = (1-x)\cdot E$ , $U = x\cdot E$ , for $0 < x < 1$

Position C

$K = 0$ , $U = E$

Explanation:

Let suppose that ball-Earth system represents a conservative system. By Principle of Energy Conservation, total energy ( $E$ ) is the sum of gravitational potential energy ( $U$ ) and translational kinetic energy ( $K$ ), all measured in joules. In addition, gravitational potential energy is directly proportional to height ( $h$ ) and translational kinetic energy is directly proportional to the square of velocity.

Besides, gravitational potential energy is increased at the expense of translational kinetric energy. Then, relative amounts at each position are described below:

Position A/Position E

$K = E$ , $U = 0$

Position B/Position D

$K = (1-x)\cdot E$ , $U = x\cdot E$ , for $0 < x < 1$

Position C

$K = 0$ , $U = E$

3 0

2 years ago

The greater the pull of gravity on an object, the greater the what of that object

Nikitich [7]

Answer:

weight

Explanation:

" the greater the pull of gravity on an object, the greater the weight of that object." In physics, weight is measured in newtons (N), the common unit for measuring force.

3 0

3 years ago

While driving, which of the following principles should be used to keep the appropriate distance between your vehicle and the ve

Alex787 [66]

The correct answer for this question is "Two-car length rule." While driving, the principle that you should be used to keep the appropriate distance between your vehicle and the vehicle in front of you is to follow the <span>Two-car length rule. This rule is to be followed for safety.</span>

5 0

3 years ago