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abruzzese [7]
3 years ago
14

If two children, with masses of 16 kg and 25 kg, sit in seats opposite one another in a rotating merry-go-round with an arm leng

th of 1.5 m from the origin, what is the moment of inertia about the rotation axis?
Physics
1 answer:
Jlenok [28]3 years ago
4 0

Answer:

92.25 kgm^2

Explanation:

Assume both children bodies are point particles. The total moment of inertia about the rotation axis of 2 points particles of mass 16 kg and 25 kg at 1.5 m arm length is

\sum I = m_1r_1^2 + m_2r_2^2

where m_1 = 16 kg, m_2 = 25 kg are the masses of 2 children r_1 = R-2 = 1.5m are their distance to the center of rotation

\sum I = 16*1.5^2 + 25*1.5^2 = 1.5^2(16 + 25) = 92.25 kgm^2

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<em>a) increases</em>

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5 0
4 years ago
A ball is thrown straight up with a speed of 30 m/s, and air resistance is negligible. How long does it take the ball to reach t
PolarNik [594]

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3 seconds

Explanation:

Applying,

Applying,

v = u±gt................ Equation 1

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From the question,

Given: v = 0 m/s ( at the maximum height), u = 30 m/s

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6 0
3 years ago
A bucket filled with water has a mass of 54 kg and is hanging from a rope that is wound around a 0.050 m radius stationary cylin
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Answer:

The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.

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Given that,

Mass of bucket = 54 kg

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We need to calculate the magnitude of the torque the bucket produces around the center of the cylinder

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Hence, The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.

3 0
3 years ago
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