Answer:
41.0 m/s, 10.6 s
Explanation:
Given:
a = -4.8 m/s²
Δy = 165 m
v = -10.0 m/s
Find: v₀ and t
v² = v₀² + 2aΔy
(-10.0 m/s)² = v₀² + 2(-4.8 m/s²) (165 m)
v₀ = 41.0 m/s
Δy = vt − ½ at²
165 m = (-10.0 m/s) t − ½ (-4.8 m/s²) t²
165 = -10t + 2.4t²
0 = 2.4t² − 10t − 165
Solve with quadratic formula:
t = [ -(-10) ± √((-10)² − 4(2.4)(-165)) ] / 2(2.4)
t = (10 ± √1684) / 4.8
t = 10.6 s
Answer:
2.09 rad/s
Explanation:
Given that,
A toy car makes 4 laps in 12 s.
We need to find the angular velocity of the toy car. We need to find the angular velocity of the toy car.
4 laps = 25.13 rad
So,

So, the angular velocity of the toy car is 2.09 rad/s.
Answer: A
Explanation: We know that f=p*n
f=50*300=15000 Hz = 15kHz.
Have a great day! <3
Answer:
It is unsafe
Explanation:
v = Velocity of car = 34 m/s
r = Radius of turn = 190 m
= Coefficient of static friction = 0.5
m = Mass of car = 1600 kg
g = Acceleration due to gravity = 9.81 m/s²
The centripetal force is given by

The frictional force is given by

If the centripetal force is greater than the frictional force then the car will slip which makes it unsafe.
Here, the centripetal force is greater than the frictional force which makes it unsafe to drive it at that speed.
Answer:
27 m/s
will be the new velocity
Explanation:
if acceleration is 3 then it must be 3 m/s^2