Question

In a titration, 25.0 mL of a 0.40 M NaOH solution is used to neutralize 10.0 mL of HCl. Calculate the molarity of the acid.

Answer 1

The molarity of the HCl acid will be 0.001 M.

What is Neutralization ?

A neutralization reaction is when an acid and a base react to form water and a salt and involves the combination of H⁺ ions and OH⁻ ions to generate water.

This is the neutralization of a strong acid (HCl) and a strong base (NaOH), which is ruled by this equation :

HCl (aq) + NaOH (aq) → NaCl (aq) + H₂O (l)

Mole Ratio : 1 mol HCl : 1 mol NaOH

Formula used ;

Molarity  = number of moles  / Volume  (in liters)

Solve for n ;

n = M × V

Substitute values and compute ;

n = 0.40 M × 0.025 liter = 0.01 moles NaOH.

As the molar ratio is NaOH : HCl

Therefore, there will be same number mole for the HCl

Now, Molarity of HCl Solution ;

Molarity = n / volume

Molarity = 0.01 / 10

             =  0.001 M HCl

Hence, The molarity of the HCl acid will be 0.001 M.

Learn more about neutralization here ;

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