An emf source with a magnitude of E = 120.0 V, a resistor with a resistance of R = 89.0 Ω, and a capacitor with a capacitance of

Question

2 years ago

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An emf source with a magnitude of E = 120.0 V, a resistor with a resistance of R = 89.0 Ω, and a capacitor with a capacitance of

C = 6.00 μF are connected in series. A) As the capacitor charges, when the current in the resistor is 0.950 A , what is the magnitude of the charge on each plate of the capacitor?

Physics

1 answer:

VikaD [51] · Answer 1 · 2023-11-17T05:26:05+03:00

For an emf source with a magnitude of E = 120.0 V, is mathematically given as

Q=136.63uC

<h3>What is the magnitude of the charge on each plate of the capacitor?</h3>

Parameters

E = 120.0 V
R = 89.0 Ω
C = 6.00 μF

Generally, the equation for voltage on the resistor is mathematically given as

Vr=IR

Therefore

Vr=71*0.95

Vr=67.45V

voltage on capacitor

Vc=120-67.45

Vc=52.55V

In conclusion,

Q=CVc

Therefore

Q=52.55*2.60

Q=136.63uC