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3 years ago

9

(IF YOU ANSWER I WILL TRY TO MARK YOU BRAINIEST!)

1 answer:

vredina [299]3 years ago

4 0

Water<span> can </span>dissolve salt<span> because the positive part of </span>water<span> molecules attracts the negative chloride ions and the negative part of </span>water<span> molecules attracts the positive sodium ions. The amount of a substance that can </span>dissolve<span> in a liquid (at a particular temperature) is called the solubility of the substance. So the solute is the salt and the solvent is the water. I believe that is correct.</span>

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The point beneath the surface where rock breaks and an earthquake is produced is known as the ______.

posledela

B. Focus is the answer.

8 0

4 years ago

Read 2 more answers

A sports car moving at constant speed travels 164 m in 13.77 s. If it then brakes and comes to a stop in 3.6 s. What is its acce

Sergio039 [100]

Answer:

a = - 0.3376 g's

Explanation:

The sports car has a constant speed when travelling. Covered 164 m in 13.77 s. Thus, speed = 164/13.77 m/s

It brakes and now comes to a stop in 3.6 s.

Thus final velocity = 0 m/s

Formula for acceleration is;

a = (v - u)/t

a = (0 - (164/13.77))/3.6

a = -3.308 m/s²

In terms of g's", where 1.00 g = 9.80 m/s², we have;

a = -3.308/9.8 g's

a = - 0.3376 g's

4 0

3 years ago

The triceps muscle in the back of the upper arm is primarily used to extend the forearm. Suppose this muscle in a professional b

taurus [48]

Answer:

I = 0.483 kgm^2

Explanation:

To know what is the moment of inertia I of the boxer's forearm you use the following formula:

$\tau=I\alpha$ (1)

τ: torque exerted by the forearm

I: moment of inertia

α: angular acceleration = 125 rad/s^2

You calculate the torque by using the information about the force (1.95*10^3 N) and the lever arm (3.1 cm = 0.031m)

$\tau=Fr=(1.95*10^3N)(0.031m)=60.45J$

Next, you replace this value of τ in the equation (1) and solve for I:

$I=\frac{\tau}{\alpha}=\frac{60.45Kgm^2/s ^2}{125rad/s^2}=0.483 kgm^2$

hence, the moment of inertia of the forearm is 0.483 kgm^2

8 0

3 years ago

Write this number in standard notation.<br> 4.702 x 10–4

iragen [17]

Move the decimal three places to the left -> .0004702

6 0

4 years ago

Read 2 more answers

If the velocity of a pitched ball has a magnitude of 47.0 m/s and the batted ball's velocity is 50.5 m/s in the opposite directi

Naya [18.7K]

Answer:

The magnitude of change in momentum of the ball is $97.5 m$ and impulse is also $97.5 m$

Explanation:

Given:

Velocity of a pitched ball $v _{i} = 47$ $\frac{m}{s}$

Velocity of ball after impact $v_{f} = -50.5$ $\frac{m}{s}$

From the formula of change in momentum,

$\Delta P = m (v_{f} -v_{i} )$

Here mass is not given in question,

Mass of ball is $m$

Change in momentum is given by,

$\Delta P = m (-50.5 -47)$

$\Delta P = -97.5 m$

Magnitude of change in momentum is

$\Delta P = 97.5 m$

And impulse is given by

$J = \Delta P$

$J = -97.5 m$

So impulse and

Therefore, the magnitude of change in momentum of the ball is $97.5 m$ and impulse is also $-97.5 m$

6 0

3 years ago