C. Electrical current increases as resistance decreases
If the light of wavelength 700 nm strikes such a photocathode the maximum kinetic energy, in eV, of the emitted electrons is 0.558 eV.
so - $KE_{max} = hc/lembda} work
threshold when KE = 0
hc/lambda = work = 1240/900=1.38 eV
b) Kemax = hc/lambda - work = 1240/640 -1.38=0.558 eV
What is photocathode?
- A photocathode electrolyte interface can be used in a photoelectrolysis cell as the primary light-harvesting junction (in conjunction with an appropriate electrochemical anode) or as an optically complementary photoactive half-cell in a tandem photoelectrode photoelectrolysis cell (Hamnett, 1982; Kocha et al, 1994).
- In the case of the former, the electrode should ideally harvest photon energy across the majority of the solar spectrum in order to achieve the highest energy conversion efficiency possible.
- In the latter case, however, the photocathode may only be active in a specific band of the solar spectrum in order to generate a cathodic photocurrent sufficient to match the current generated in the photoanodic half-cell.
To learn more about Photocathode from the given link:
brainly.com/question/9861585
#SPJ4
The electric potential energy of this system of charges will be +1.44 J. Option E is correct.
<h3>What is the electric potential energy ?</h3>
Electric potential energy stands for the energy that is required to displace a charge in against an electric field.
Given data;
q₁ = 4. 0 µc
q₂ = -8. 0 µc
D(distance between charges) = 0.2 m
The electric potential energy is found as;
The electric potential energy of this system of charges will be +1.44 J.
Hence,option E is correct.
To learn more about the electric potential energy refer:
brainly.com/question/12645463
#SPJ4
<span>Mass is inversely proportional to energy. The larger the mass, the smaller will be the energy.</span>
Answer:
1235.5J
Explanation:
Given parameters:
Mass of car = 2413kg
Speed of car = 32m/s
Unknown:
Amount of kinetic energy it has = ?
Solution:
Kinetic energy is the energy due to the motion of a body;
Kinetic energy = 
m v²
m is the mass
v is the velocity
Now insert the parameters;
Kinetic energy = x 2413 x 32² = 1235.5J
