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skad [1K]
2 years ago
6

A marble rolls off a table from a height of 1.5 meters. Approximately how much time was the marble in the air?

Physics
1 answer:
sergij07 [2.7K]2 years ago
7 0

Answer:

t = 0.55 s

Explanation:

Given that,

Height of the marble, h = 1.5 m

We need to find the time for which the marble is in air. Let the time is t. Using second equation of motion to find it as follows :

h=ut+\dfrac{1}{2}at^2

Here, u = 0 and a = g

h=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\cdot1.5}{9.8}}\\\\t=0.55\ s

So, the marble is in air for 0.55 s. Hence, the correct option is (c).

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