Question

A marble rolls off a table from a height of 1.5 meters. Approximately how much time was the marble in the air?

Answer 1

Answer:

t = 0.55 s

Explanation:

Given that,

Height of the marble, h = 1.5 m

We need to find the time for which the marble is in air. Let the time is t. Using second equation of motion to find it as follows :

$h=ut+\dfrac{1}{2}at^2$

Here, u = 0 and a = g

$h=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\cdot1.5}{9.8}}\\\\t=0.55\ s$

So, the marble is in air for 0.55 s. Hence, the correct option is (c).