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2 years ago

Which of the following are products when magnesium metal is placed in hydrochloric acid? (Correct answer should be D but why)

Chemistry

2 answers:

Kruka [31]2 years ago

8 0

Answer:

an acid +metal =salt +hydrogen

Explanation:

HCL+Mg =Mgcl2+H2

(because Mg has an ion with a +2 charge ,it attracts Cl with a -2 charge )

therefore the correct answer is D for the above reasons

Alexus [3.1K]2 years ago

7 0

Answer:

When magnesium reacts with hydrochloric acid (HCl), a single-replacement reaction occurs. These reactions involve the substitution of one element in a compound with another. In this case, the hydrogen in HCl will be swapped with the magnesium metal because both of these elements make cations (positively-charged ions) when they participate in ionic bonding.

So why does the chorine have a subscript of 2 when it bonds with magnesium? This occurs in order to balance the ionic charges and make the overall compound neutral.

Magnesium wants to give away 2 electrons when it ionizes, forming the cation Mg²⁺. However, chlorine only wants to gain 1 electron to fill its valence shell, making it form the anion, Cl⁻. As you can see, if just one of each ion were to bond, the compound would have an overall charge of +1 because (+2 - 1 = +1). Therefore, the compound can be made neutral if two chlorine ions bond with just 1 magnesium ion (+2 - 1 - 1 = 0).

The hydrogen ion from HCl becomes H₂ after the reaction occurs. This occurs because hydrogen generally exists as a diatomic compound in nature (diatomic = exists as 2 atoms).

The complete balanced equation for the reaction is:

Mg + 2 HCl ------> MgCl₂ + H₂

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Given the partial equation:

Nikolay [14]

Answer : The balanced chemical equation in acidic medium will be,

$IO_3^-(aq)+2Sn^{2+}(aq)+6H^+(aq)\rightarrow I^-(aq)+2Sn^{4+}(aq)+3H_2O(l)$

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Rules for the balanced chemical equation in acidic solution are :

First we have to write into the two half-reactions.

Now balance the main atoms in the reaction.

Now balance the hydrogen and oxygen atoms on both the sides of the reaction.

If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the less number of oxygen are present.

If the hydrogen atoms are not balanced on both the sides then adding hydrogen ion $(H^+)$ at that side where the less number of hydrogen are present.

Now balance the charge.

The given chemical reaction is,

$IO_3^-(aq)+Sn^{2+}(aq)\rightarrow I^-(aq)+Sn^{4+}(aq)$

The oxidation-reduction half reaction will be :

Oxidation : $Sn^{2+}\rightarrow Sn^{4+}$

Reduction : $IO_3^-\rightarrow I^-$

First balance the main element in the reaction.

Oxidation : $Sn^{2+}\rightarrow Sn^{4+}$

Reduction : $IO_3^-\rightarrow I^-$

Now balance oxygen atom on both side.

Oxidation : $Sn^{2+}\rightarrow Sn^{4+}$

Reduction : $IO_3^-\rightarrow I^-+3H_2O$

Now balance hydrogen atom on both side.

Oxidation : $Sn^{2+}\rightarrow Sn^{4+}$

Reduction : $IO_3^-+6H^+\rightarrow I^-+3H_2O$

Now balance the charge.

Oxidation : $Sn^{2+}\rightarrow Sn^{4+}+2e^-$

Reduction : $IO_3^-+6H^++4e^-\rightarrow I^-+3H_2O$

The charges are not balanced on both side of the reaction. Thus, we are multiplying oxidation reaction by 2 and the adding both equation, we get the balanced redox reaction.

Oxidation : $2Sn^{2+}\rightarrow 2Sn^{4+}+4e^-$