The % yield of Ca(OH)₂ : 62.98%
<h3>Further eplanation
</h3>
Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated
General formula:
Percent yield = (Actual yield / theoretical yield )x 100%
An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients
Reaction
CaO + H₂O ⇒ Ca(OH)₂
mass CaO= 4.2 g
mol CaO(MW=56,0774 g/mol) :

mol Ca(OH)₂ based on mol CaO
mol ratio CaO : Ca(OH)₂,= 1 : 1, so mol Ca(OH)₂ = 0.075
mass Ca(OH)₂(MW=74,093 g/mol) ⇒ theoretical

% yield :

Answer:
<h2>Density = 0.2 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
<h3>

</h3>
From the question the points are
mass = 6.8 g
volume = 34 mL
Substitute the values into the above formula and solve
That's
<h3>

</h3>
We have the final answer as
<h3>Density = 0.2 g/mL</h3>
Hope this helps you
Anything greater that 7 is a base....so 13 would be a very strong base for example a drain cleaner. Hopefully this is what you are looking for.