Use PV = mRT/M and solve for R. R = PVM/RT. Since you have the same gas under two sets of conditions then you can write
<span>P1V1M1/m1T1 = P2V2M2/m2T2 </span>
<span>Since P, M and T are constant, the equation becomes </span>
<span>V1/m1 = V2/m2 </span>
<span>Now plug in your values and solve for V2</span>
Answer: B.)
Explanation: Heat flows from pan to sounroundings
Answer:
The reaction decomposes more as T increases, therefore it is ENDOTHERMIC, meaning it requires energy to form CO and O₂.
Kp for each specie...
Kp = CO^2 O2 / (CO2)^2
for
T = 1500
Assume 1 atm for CO2, after % dissociation
P-CO2 left = 1*(1-0.048/100)= 0.99952
P-CO formed = 1-0.99952 = 0.00048
P-O2 = (1-0.99952)/2 = 0.00024
so..
Kp = CO^2 O2 / (CO2)^2
Kp = (0.00048^2)(0.00024) / (0.99952^2) = 5.53*10^-11
T = 2500
Assume 1 atm for CO2, after % dissociation
P-CO2 left = 1*(1-17.6/100)= 0.824
P-CO formed = 1-0.824= 0.176
P-O2 = (1-0.176)/2 = 0.088
so..
Kp = CO^2 O2 / (CO2)^2
Kp = (0.176^2)(0.088) / (0.824^2) =0.0040
T = 3000
Assume 1 atm for CO2, after % dissociation
P-CO2 left = 1*(1-54.8/100)= 0.452
P-CO formed = 1-0.452= 0.548
P-O2 = (1-0.452)/2 = 0.274
so..
Kp = CO^2 O2 / (CO2)^2
Kp = (0.548^2)(0.274) / (0.452^2) =0.4027
Explanation:
Explanation:
(Ques- A) Why does the first method for determining volume work only for a regular-shaped object?
<u>(Ans- A)</u> <em>Because the method requires precise dimensions of objects for result, which is not possible for irregular shaped objects.</em>
(Ques - B) Will the second method for determining volume work for any object or just an odd-shaped one? Why?
<u>(Ans-B)</u> <em>It will work for both regular and irregular shaped objects since both displace equal volumes of water.</em>
(Ques - C) Is one method of measurement more accurate than the other? Why or why not?
<u>(Ans-C)</u> <em>Both are pretty accurate, with some experimental errors which may creep in accidentally. </em>
(Ques- D) Would the displacement method of measurement work for a cube of sugar? What about a cork? Why?
<u>(Ans - D)</u> <em>No, the method would not work because sugar being soluble, will dissolve in water. </em>
<em>No, the method would not work because sugar being soluble, will dissolve in water. Cork is less dense than water so floats on it, with only part of it submerged in water, resulting in displacement of less volume of water than actual volume of Cork.</em>
(Ques-E) What did you find out from this investigation? Be thoughtful in your answer.
<u>(Ans- E)</u> <em>I learnt about determining volume of different objects from this investigation. </em>(Sorry, I know its not a very thoughtful answer)
Answer : The expression for solubility constant for this reaction will be,
![K_{sp}=[Ca^{2+}]^3[PO_4^{3-}]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5E3%5BPO_4%5E%7B3-%7D%5D%5E2)
Explanation :
Solubility product : It is defined as the product of the concentration of the ions that present in a solution raised to the power by its stoichiometric coefficient in a solution of a salt. This takes place at equilibrium only.
The solubility product constant is represented as, 
.
The dissociation of calcium phosphate is written as:
The expression for solubility constant for this reaction will be,
