439.3 g CO2
Explanation:
First find the # of moles of CO2 that results from the combustion of 3.327 mol C3H6:
3.227 mol C3H6 × (6 mol CO2/2 mol C3H6)
= 9.981 mol CO2
Use the molar mass of CO2 to determine the # of grams of CO2:
9.981 mol CO2 x (44.01 g CO2/1 mol CO2)
= 439.3 g CO2
Answer:
0°C and 1 atm
Explanation:
This are the conditions of temperature and pressure defined by IUPAC as standard.
But also, the definition used by the NIST considerates a temrperature of 20°C and a pressure of 1 atm
1. D
2. <span>83.5 million years ago - 66 million years ago
3. </span><span>It had armor and could rotate to keep its caudal bludgeon facing the enemy.
hope this helped :)
alisa202</span>
