Answer:
Arrival times of P and S waves
Explanation:
Seismological recording station has a seismometer that senses that motion in the ground, a clock that records time and a data recorded.
The distance between beginning of the first P wave and the first S wave will give you the time the waves are apart.This time value will be used to find the distance between the seismograph and the epicenter of earthquake and you mark it.This is corresponding distance in km to the time in seconds obtained before.You then find the amplitude of the strongest wave and mark it on the right side of chart.Amplitude is the height on paper of the strongest wave.Using a ruler join the amplitude point and the point where you marked the distance to epicenter.This line will cross the magnitude chart at a point which represents the magnitude of the Earthquake.
Horizontal angulation is Select one: a. the side-to-side angulation. b. different when using the paralleling and bisecting techniques.
Angles that are horizontal. relates to the central ray's placement in a horizontal, or side-to-side, plane.
A picture with an overlap of nearby structures in the horizontal plane is produced by situating the central ray such that the horizontal angulation is not directed through the interproximal contacts of the adjacent teeth (the contact areas of the teeth are superimposed over each other).
Fracture angulation refers to a particular kind of fracture displacement in which the bone's natural axis has been changed so that the distal end now points off in a different direction. When using a bite-wing tab, the x-ray beam's center ray must be pointed at the contact points between teeth. The x-ray beam must be centered on the receptor to guarantee that the receptor is exposed.
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The reactance of an inductor is given by:
X = 2πfL
X is the inductor's reactance
f is the frequency of the supplied voltage
L is the inductor's inductance
The given values are:
f = 60.0Hz
L = 43.8mH (I'm assuming the value is given in milli Henries because this is within the normal range of inductors)
Plug these values in and solve for X:
X = 2π(60.0)(43.8×10⁻³)
X = 16.512Ω
Round this value to 3 significant figures:
X = 16.5Ω
The relationship between AC voltage and current is given by:
V = IZ
V is the voltage
I is the current
Z is the impedance
For an AC inductor circuit, Z = X = 16.512Ω and V is the rms voltage 120V. Plug these values in to get the rms current:
120 = I×16.512
I = 7.2673A
Round this value to 3 significant figures:
I = 7.27A