As we know that centripetal acceleration is given as

here we know that
linear speed = 35 m/s
here radius of path is same as length of arm
R = 0.7 m
now from above above formula we have


so acceleration is 1750 m/s/s
Answer:
g' = g/9 = 1.09 m/s²
Explanation:
The magnitude of free fall acceleration at the surface of earth is given by the following formula:
g = GM/R² ----- equation 1
where,
g = free fall acceleration
G = Universal Gravitational Constant
M = Mass of Earth
R = Distance between the center of earth and the object
So, in our case,
R = R + 2 R = 3 R
Therefore,
g' = GM/(3R)²
g' = (1/9) GM/R²
using equation 1:
g' = g/9
g' = (9.8 m/s)/9
<u>g' = 1.09 m/s²</u>
It goes in this order. Medium, density, viscosity
On a planet with different gravity, the molarity of water won't be different as water produces regular natural gravity.
<h3>How to explain the gravity?</h3>
Although sunlight is the energy source, gravity is the main factor driving the water cycle. The Earth's gravity pulls matter downward and toward its center. Gravity is the force that attracts two objects. It pushes water downhill and precipitation from the clouds. Air and ocean water are also moved by gravity.
We understand that even if the gravitational pull varies throughout the universe, the molarity of water would be constant everywhere. This is thus because a substance's mass is unaffected by gravity; only its weight is. The quantity (or mass, indirectly) of a solute is used to calculate the molarity.
Here, on a planet with different gravity, the molarity of water won't be different as water produces regular natural gravity.
Learn more about gravity on:
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The final vertical velocity of the object is 705.6 m
Explanation:
Here we have to analyze the vertical motion of the object, which is a free fall motion, with constant acceleration of

towards the ground due to gravity.
Therefore, we can use the following suvat equation:

where
v is the final vertical velocity
u is the initial vertical velocity
is the acceleration
t is the time
Since the object is dropped,
u = 0
Therefore, the magnitude of the vertical velocity of the object after t = 72 seconds is:

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