All categories

3 years ago

Like electric charges repel each other. Please select the best answer from the choices provided

Physics

2 answers:

alexdok [17]3 years ago

7 0

<span>Like electric charges repel each other. TRUE
I hope this helped :)</span>

g100num [7]3 years ago

3 0

Answer: Option (a) is the correct answer.

Explanation:

It is true that like charges repel each other because their line of force repel each other.

For example, when two positively charged ions are placed together then they tend to repel each other.

Whereas unlike charges attract each other.

For example, when we place a negative charge near a positive charge then the positive charge will readily get attracted to the negative charge because the line of force also attract each other.

You might be interested in

Where does most of earths available carbon come from

cupoosta [38]

Rocks and sediments I believe

6 0

3 years ago

When thorium (90 protons) ejects a beta particle, the resulting nucleus has

Sav [38]

Answer:

none of the above

Explanation:

The actual answer is '91 protons'. In fact, the beta decay of the thorium-234 is the following:

${}_{90}Th \rightarrow {}_{-1}e+{}_{91}Pa$

where inside the nucleus of Thorium (90 protons), a neutron turns into an electron (the beta particle) + a proton. Therefore, the resulting nucleus (which is Protoactinium) has a total of 90+1 = 91 protons.

So, the correct answer would be '91 protons'.

7 0

3 years ago

In doing a load of clothes, a clothes dryer uses 16 A of current at 240 V for 45 min. A personal computer, in contrast, uses 2.7

jasenka [17]

Explanation:

Given that,

Current of clothes dryer, I = 16 A

Voltage, V = 240 V

Time, t = 45 min = 2700 s

Current of personal computer, I' = 2.7 A

Voltage, V' = 120 C

Energy used by clothes dryer is given by :

$E=I^2Rt\\\\E=IVt\\\\E=16\times 240\times 2700\\E=1.03\times 10^7\ J$

Let t' is the time for this computer to "surf" the internet. Again using formula of energy used as :

$E=I'V't'\\\\t'=\dfrac{E}{I'V'}\\\\t'=\dfrac{1.03\times 10^7}{2.7\times 120}\\\\t'=31790.12\ s\\\\t'=8.83\ h$

So, for 8.83 hours you could use this computer to "surf" the internet.

6 0

3 years ago

To make 2 molecules of water, you need 2 molecules of hydrogen plus 1 molecule of oxygen. If I have unlimited amounts of oxygen

Semenov [28]

Hey there,

So first we need to know how much molecules are there in 4 grams of hydrogen right?
In one gram of hydrogen there are 6.0221415 multiplied by 10^25 molecules right?(this number is known as avagadors constant )

And to make one molecule of water u need two molecules of hydrogen and one of oxygen.
And oxygen is unlimited right?

So when we have 6.0221415 grams of hydrogen tow if these are required to make one water.
So divide that by two and you get 3.0110704 multiplied by 10^25.
So the answer is you can make the above number of water molecules.

Hope this helps!!!

5 0

3 years ago

The biological roles of complex organic molecules are determined by their shape -- the way atoms and electrons create charge dis

Hatshy [7]

Answer:

a) P_α = exp (-ΔE / kT), b) P_β = 0.145 , d) ΔE = 309.7 meV

Explanation:

The expression for the number of molecules or particles in a given state in Boltzmann's expression

n = n₀ exp (-ΔE / kT)

Where k is the Bolztmann constant and T the absolute temperature

The probability is defined as the number of molecules in a given state over the total number of particles

P = n / n₀ = exp (- ΔE / kT)

Let's apply this expression to our case

a) P_α = n_α / n₀ = exp (-ΔE / kT)

b) the Boltzmann constant

k = 1,381 10⁻²³ J / K (1 eV / 1.6 10⁻¹⁹ J) = 8.63 10⁻⁵ eV / K

kT = 8.63 105 300 = 2,589 10⁻² eV

P_β = exp (- 50 10⁻³ /2.589 10⁻² = exp (-1.931)

P_β = 0.145

c) If the temperature approaches absolute zero, the so-called is very high, so there is no energy to reach the excited state, therefore or all the molecules go to the alpha state

d) For molecules to spend ¼ of the time in this beta there must be ¼ of molecules in this state since the decay is constant.

P_β = ¼ = 0.25

P_β = exp (- ΔE / kT)

ΔE = -kT ln P_β

ΔE = - 2,589 10⁻² ln 0.25

ΔE = 0.3097 eV

ΔE = 309.7 meV

3 0

3 years ago