Answer:
2. 4.63 x 10 to the -11th power
Explanation:
m1 = 3.1, m2= 6.3, d = 5.3, G = 6.67 × 10^-11
m1 · m2 = 3.1 · 6.3 = 19.5
d² = 5.3² = 28.1
19.5/28.1 = 0.694
(6.67 · 10^-11) · 0.694 = 4.63 × 10^-11
Answer:

Explanation:
Conceptual analysis
To solve this problem we apply Newton's second law:
The acceleration of an object is proportional to the force F acting on it and inversely proportional to its mass m.
a = F / m
Where,
F = m * a Formula (1)
F: Force in Newtons (N)
m: mass in kg
a: acceleration in m/(s^2)
a = v / t Formula (2)
v: speed in m/s
t: time in seconds (s)
Known information
We know the following data:
m = 1kg
v = 1 m/s
t = 1s
Development of the problem:
In the Formula (2): 
In the Formula (1): 
As a horse finishes its trot around the corral, it slows from 4m/s to a stop in 3
seconds. Calculate the acceleration of the horse.
Can anybody help ?
Latent heat fusion(l)=540
∆t= temp(100-0)
Q=ml+ms∆T
Q=500.100+100.1.100
Q=64000 cal