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2 years ago

Find the location of the center of mass of the earth-moon system relative to the center of earth.

Physics

1 answer:

mamaluj [8]2 years ago

8 0

Answer:

4765 Km

Explanation:

The center of mass for a two point system is given by the formula:

CM= (mass earth x distance of cm to centre of earth + mass moon x distance of cm to moon ) / mass earth + mass moon

mass earth: 5.97 x 10^24 Kg

mass moon: 7.35 x 10^22 Kg

distance earth-moon = 384,400 Km : 3.84 x 10^6 m

The center of mass will be located between the line distance joining the earth moon but since we are told to calculate relative to the center of earth ,the distance from earth to the center of mass is cero making our calculations easier.

CM = (5.97 x 10 ^24 x 0 + 7.35 x 10 ^22 x 3.84 x 10 ^6 )/ (5.97 x 10^24 + 7.35 x 10^22)

CM= 7.35 x 10 ^22 x 3.84 x 10 ^6/ ( 6.04 x 10 ^24) m = 4.765 x 10 ^6 m = 4765 Km

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If the distance between two masses is tripled, the gravitational force between changes by a factor of

maw [93]

A. 1/9

Explanation:

The gravitational force between two objects is given by

$F=G\frac{m_1 m_2}{r^2}$

where

G is the gravitational constant

m1 and m2 are the two masses

r is the distance between the two masses

From the formula, we see that the magnitude of the force is inversely proportional to the square of the distance: therefore, if the distance is tripled (increased by a factor 3), the magnitude of the force changes by a factor

$\frac{1}{r^2}=\frac{1}{3^2}=\frac{1}{9}$

6 0

2 years ago

Read 2 more answers

Bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving -1.72 m/s. What is the veloc

Nuetrik [128]

The velocity of B after elastic collision is 3.45m/s

This type of collision is an elastic collision and we can use a formula to solve this problem.

<h3>Elastic Collision</h3>

$v_2 = \frac{2m_1u_1}{m_1+m_2} - \frac{m_1 - m_2}{m_1 + m_2}u_2$

The data given are;

m1 = 281kg
u1 = 2.82m/s
m2 = 209kg
u2 = -1.72m/s
v1 = ?

Let's substitute the values into the equation.

$v_1 = \frac{2*281*2.82}{281+209} -\frac{281-209}{281+209}(-1.72)\\v_1 = 3.45m/s$

From the calculation above, the final velocity of the car B after elastic collision is 3.45m/s.

Learn more about elastic collision here;

brainly.com/question/7694106

4 0

1 year ago

Question 1 of 15

Ierofanga [76]

Answer:

d 75 miles per hour

Explanation:

60 ÷ 20

3 × 25 = 75

hoped that helped!!

8 0

2 years ago

A ball is kicked from a location 7, 0, −8 (on the ground) with initial velocity −11, 19, −5 m/s. The ball's speed is low enough

Alja [10]

Answer:

$\vec{v} =$

Explanation:

given,

location of the ball ⟨7,0,−8⟩

initial velocity of the ball ⟨-11,19,−5⟩

time = 0.4 s

speed of the ball = ?

using Momentum Principle

change in momentum = Force x time

$m \vec{v} - m \vec{u}= \vec{F}\times \Delta t$

$\vec{v} =\vec{u} + \dfrac{\vec{F}}{m}\times \Delta t$

Net force acting in this case will be equal to force due to gravity because air resistance is negligible.

F_net = F_g = ⟨0 ,-9.8 m , 0⟩

now,

$\vec{v} = + \dfrac{}{m}\times (0.4-0)$

$\vec{v} = +$

$\vec{v} =$

hence, the velocity of the ball 0.4 s after being kicked is equal to $\vec{v} =$

5 0

2 years ago

(b) Cable of a microwave oven has three wires inside it which have insulation of different colours black, green and red. Mention

MakcuM [25]

The green is ground. Ideally, no current travels in this one. The red and black are the power and neutral wires but which colors they are depends on a convention. In the US, you will actually have a black (power) and a white (neutral) Here it's red and black and usually in a red/black system the red is the power. Either way there is a potential of 120V rms between them.

8 0

2 years ago