All categories

2 years ago

Find the location of the center of mass of the earth-moon system relative to the center of earth.

Physics

1 answer:

mamaluj [8]2 years ago

8 0

Answer:

4765 Km

Explanation:

The center of mass for a two point system is given by the formula:

CM= (mass earth x distance of cm to centre of earth + mass moon x distance of cm to moon ) / mass earth + mass moon

mass earth: 5.97 x 10^24 Kg

mass moon: 7.35 x 10^22 Kg

distance earth-moon = 384,400 Km : 3.84 x 10^6 m

The center of mass will be located between the line distance joining the earth moon but since we are told to calculate relative to the center of earth ,the distance from earth to the center of mass is cero making our calculations easier.

CM = (5.97 x 10 ^24 x 0 + 7.35 x 10 ^22 x 3.84 x 10 ^6 )/ (5.97 x 10^24 + 7.35 x 10^22)

CM= 7.35 x 10 ^22 x 3.84 x 10 ^6/ ( 6.04 x 10 ^24) m = 4.765 x 10 ^6 m = 4765 Km

You might be interested in

Identify the physical property of a material that is NOT a good conductor of heat.

EleoNora [17]

Answer:D.no of the above

Explanation:get right with Christ

4 0

3 years ago

Which instrument is used to measure depth of ocean ?

skelet666 [1.2K]

Echo sounding is a type of SONAR used to determine the depth of water by transmitting sound pulses into water. The time interval between emission and return of a pulse is recorded, which is used to determine the depth of water along with the speed of sound in water at the time.

5 0

2 years ago

Calculate the magnitude of the acceleration due to gravity on the surface of Earth due to the Moon.

Fudgin [204]

Answer:

$g'_h=1.096\times 10^{-5}\ m.s^{-2}$

Explanation:

We know that the gravity on the surface of the moon is,

$g'=\frac{g}{6}$

$g'=1.63\ m.s^{-2}$

<u>Gravity at a height h above the surface of the moon will be given as:</u>

$g'_h=\frac{G.m}{(r+h)^2}$ ..........................(1)

where:

G = universal gravitational constant

m = mass of the moon

r = radius of moon

We have:

$G=6.67\times 10^{-11}\ m^3.s^{-2}.kg^{-1}$

$m=7.35\times 10^{22}\ kg$

$r=1.74\times 10^6\ m$

$h=384.4\times 10^6\ m$ is the distance between the surface of the earth and the moon.

Now put the respective values in eq. (1)

$g'_h=\frac{6.67\times 10^{-11}\times 7.35\times 10^{22}}{(1.74\times 10^6+384.4\times 10^6)^2}$

$g'_h=1.096\times 10^{-5}\ m.s^{-2}$ is the gravity on the moon the earth-surface.

4 0

3 years ago

What is your basal metabolism

Arada [10]

It's the energy your body spends to just keep you breathing and your heart beating ... just being alive, without trying to DO anything.

5 0

2 years ago

Acid mine drainage is:

Dahasolnce [82]

Answer:

Acid mine drainage is dissolved toxic materials wash from mines into nearby lakes and streams.

Explanation:

Acid mine drainage is the flow of acidic water with pH typically between 2 and 4, and high concentrations of other dissolved toxic materials from mines into nearby lakes and streams. It mainly occurs during metal sulfide mining, when the metal sulfide ore such as pyrite (FeS2) is exposed to water and oxygen from air to produce soluble iron and sulfuric acid.

Microorganisms, especially acidophile bacteria like Acidithiobacillus ferrooxidans grow by pyrite oxidation, i.e., oxidizing the Fe²⁺ in pyrite to Fe³⁺, which again react with pyrite and water to produce sulfuric acid. Then the acidic water flows into nearby water sources and reduces the pH value of water in those sources. As a result, heavy metals such as copper, lead, mercury, etc in other mineral ores also get dissolved into the water. The action of acidophile bacteria also increases the rate and degree of acid-mine drainage process.

The acid mine drainage causes water pollution and adversely affect the aquatic plants and animals. It also results in the contamination of drinking water, corrosion of infrastructures such as bridges, etc.

8 0

3 years ago