All categories

1 year ago

1. A sample of a gas is occupying a 500 mL container at a pressure of 1.4 atm and a temperature of 25 °C.

1 answer:

4 0

The new volume of a sample of gas initially occupying a 500 mL container at a pressure of 1.4 atm and a temperature of 25 °C is 281.01mL.

<h3>How to calculate volume?</h3>

The volume of a gas can be calculated using the following formula:

P1V1//T1 = P2V2/T2

Where;

P1 = initial pressure
P2 = final pressure
V1 = initial volume
V2 = final volume
T1 = initial temperature
T2 = final temperature

1.4 × 500/298 = 2.7 × V2/323

2.348 × 323 = 2.7V2

758.72 = 2.7V2

V2 = 281.009mL

Therefore, the new volume of a sample of gas initially occupying a 500 mL container at a pressure of 1.4 atm and a temperature of 25 °C is 281.01mL.

Learn more about volume at: brainly.com/question/1578538

#SPJ1

You might be interested in

In 1990, the northern spotted owl was listed as endangered. Because of this, millions of acres of forests in the Pacific

Gwar [14]

Answer:

the endangered spices act

Explanation: The US Endangered Species Act (ESA) is our nation's most effective law to protect at-risk species from extinction, with a stellar success rate: 99% of species listed on it have avoided extinction.

8 0

2 years ago

There are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with

grandymaker [24]

$\text{Hg} \text{O}$ and $\text{Hg}_{2} \text{O}$ .

Assuming complete decomposition of both samples,

$m(\text{Hg}) = m(\text{residure})$
$m(\text{O}) = m(\text{loss})$

First compound:

$m(\text{O}) = m(\text{loss}) = 0.6498 - 0.6018 = 0.048 \; g$
$m(\text{Hg}) = m(\text{residure}) = 0.6018 \; g$

$n = m/M$ ; $0.6498 \; g$ of the first compound would contain

$n(\text{O atoms}) = 0.048 \; g / 16 \; g \cdot mol^{-1}= 0.003 \; mol$
$n(\text{Hg atoms}) = 0.6018 \; g / 200.58 \; g \cdot mol^{-1}= 0.003 \; mol$

Oxygen and mercury atoms seemingly exist in the first compound at a $1:1$ ratio; thus the empirical formula for this compound would be $\text{Hg} \text{O}$ where the subscript "1" is omitted.

Similarly, for the second compound

$m(\text{O}) = m(\text{loss}) = 0.016 \; g$
$m(\text{Hg}) = m(\text{residure}) = 0.4172 - 0.016 = 0.4012 \; g$

$n = m/M$ ; $0.4172 \; g$ of the first compound would contain

$n(\text{O atoms}) = 0.016 \; g / 16 \; g \cdot mol^{-1}= 0.001 \; mol$
$n(\text{Hg atoms}) = 0.4012 \; g / 200.58 \; g \cdot mol^{-1}= 0.002 \; mol$

$n(\text{Hg}) : n(\text{O}) \approx 2:1$ and therefore the empirical formula

$\text{Hg}_{2} \text{O}$ .

8 0

2 years ago

Which term best describes this reaction? 2 carbons double bonded to each other, with CH 3 above the left C and H above the right

Ierofanga [76]

Answer:

addition polymerization

Explanation:

In addition polymerization, the monomers are simply joined to each other to form a polymer having the same empirical formula as the monomer but of higher relative molecular mass. The monomers in addition polymerization are usually simple unsaturated molecules such as alkenes.

We can deduce the reaction to be an addition polymerization because of the the attachment of n to both the unsaturated monomer and the saturated polymer without the loss of any small molecule. If it was a condensation polymerization, there would have been an accompanying loss of a small molecule such as water.

6 0

3 years ago

Classify the following materials as solid, liquid, or gas at room temperature: milk, helium, granite, oxygen, steel, and gasolin

Sati [7]

Im not sure but milk is liquid, helium is gas, granite is solid, oxygen is gas, steel is solid, and gasiloine is liquid.

3 0

2 years ago

Why less electro negative elements are taken as central atom

sladkih [1.3K]

Answer:

The least electronegative elements in the center of lewis structures because an atom in the central position shares more of its electrons than does a terminal atom. Atoms with higher electronegative are generally more reluctant to share their electrons.

Explanation:

3 0

2 years ago