Question

Example No. 10

Answer 1

The force constant of the spring is determined as 14,222.2 N/m.

Force constant of the spring

Apply the principle of conservation of energy,

K.E = U

where;

• K.E kinetic energy of the elevator
• U is elastic potential energy of the spring

¹/₂mv² = ¹/₂kx²

mv² = kx²

k = mv²/x²

Where;

• m is mass of the elevator
• v is speed
• x is compression of the spring

k = (2000 x 8²)/(3²)

k = 14,222.2 N/m

Thus, the force constant of the spring is determined as 14,222.2 N/m.

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