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3 years ago

Acceleration with motion graphs please help

Physics

1 answer:

sattari [20]3 years ago

8 0

The acceleration of the car in section C is -3 m/s/s

Explanation:

The acceleration of a body is defined as:

$a=\frac{\Delta v}{\Delta t}$

where

$\Delta v$ is the change in velocity of the body

$\Delta t$ is the time it takes for the body to change its velocity by $\Delta v$

We notice that in a graph of velocity vs time, the slope of the graph is

$m=\frac{\Delta v}{\Delta t}$

So we see that the slope of the graph corresponds to the acceleration of the object.

In section C of this graph, we have:

$\Delta v = v-u=6 m/s - 12 m/s = -6 m/s$ is the change in velocity of the object

$\Delta t = 11 s - 9 s = 2 s$ is the time interval

Therefore, the slope of the graph (and so, the acceleration of the car) in section C is:

$a=\frac{-6}{2}=-3 m/s^2$

Learn more about acceleration here:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

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Całą część pytania można znaleźć na poniższym schemacie.

Z diagramu załączonego poniżej; mamy

A - samolot lotniczy

B - dźwig

C - podnoszenie ciężarów

Wszyscy to wiemy ;

1kJ = 1000 J

1MJ = 1000000 J

Mamy cztery opcje; i.e 200 MJ, 800 kJ, 1.6 kJ and 250 mJ

Z czterech opcji można wykluczyć 250 mJ, ponieważ jest to 0,25 J, co przedstawia bardzo niską energię w porównaniu z trzema warunkami pokazanymi na schemacie.

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Największą pracę wykona samolot. Jest tak, ponieważ ma bardzo dużą masę i bardzo dużą prędkość. W związku z tym istnieje potrzeba wytworzenia ogromnej ilości ciepła i energii.

Z drugiej strony żuraw może podnieść ładunek o wiele większy i przewyższa ciężar ciężaru, więc praca wykonywana przez dźwig musi być zdecydowanie większa niż praca ciężarka.

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