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3 years ago

In order for an object to sink, its density must ___________ 1g/ml.

Physics

2 answers:

Tju [1.3M]3 years ago

7 0

In order for an object to sink, its density must be greater than 1g/ml.

scoundrel [369]3 years ago

7 0

be greater than

Hope this helped

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What is the de Broglie wavelength for a proton with energy 50 keV? Due to the limitations of Canvas, please give the wavelength

ad-work [718]

Answer:

1.2826 x 10^-13 m

Explanation:

$\lambda = \frac{h}{\sqrt{2 m K}}$

Here, k be the kinetic energy and m be the mass

K = 50 KeV = 50 x 1.6 x 10^-16 J = 80 x 10^-16 J

m = 1.67 x 10^-27 kg

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λ = 1.2826 x 10^-13 m

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3 years ago

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Questions Two cyclists, 42 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?

Start of Answer:

-- When they started, they were 42 miles apart. When they met, 2 hours later, they were no miles apart. The distance between them shrank at the rate of 21 miles per hour. Since they rode directly toward each other, the sum of their individual speeds must have been 21 miles per hour.

-- One biker was two times the speed of the other. Slower biker: 1 time. Faster biker: 2 times. Sum of their speeds: 3 times = 21 miles per hour. Each 'time' = 7 miles per hour.

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3 years ago

Any example of acceleration related to human body??? answer quickly plz :)

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Answer:

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2 years ago

Why do the passengers on a high-flying airplane not appear weightless, similar to the astronauts on the space station?

sergey [27]

Even in space, there is still presence of gravity. The cause of weightlessness is not how far above the earth the space shuttle is but rather how fast it is travelling. The shuttle is in free fall causing weightlessness, but it is travelling fast enough to miss the earth as it falls. Similarly, the airplane could also provide weightlessness if it went free fall as well. However, that ends as the plane hits the ground.

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3 years ago

In an elastic collision, a 580 kg bumper car collides directly from behind with a second, identical bumper car that is traveling

kozerog [31]

Answer: vl = 2.75 m/s vt = 1.5 m/s

Explanation:

If we assume that no external forces act during the collision, total momentum must be conserved.

If both cars are identical and also the drivers have the same mass, we can write the following:

m (vi1 + vi2) = m (vf1 + vf2) (1)

The sum of the initial speeds must be equal to the sum of the final ones.

If we are told that kinetic energy must be conserved also, simplifying, we can write:

vi1² + vi2² = vf1² + vf2² (2)

The only condition that satisfies (1) and (2) simultaneously is the one in which both masses exchange speeds, so we can write:

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If we call v1 to the speed of the leading car, and v2 to the trailing one, we can finally put the following:

vf1 = 2.75 m/s vf2 = 1.5 m/s

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3 years ago