Express fx and fy in terms of the length of the vector f and the angle θ in paired form

Physics

1 answer:

vaieri [72.5K]3 years ago

7 0

Where Fx = Fcos(Θ) and Fy = sin(Θ)<span>
Fcos(θ),Fsin(θ)</span>

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A cat dozes on a stationary merry-go-round, at a radius of 5.5 m from the center of the ride. Then the operator turns on the rid

bixtya [17]

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$u_{s}=0.56$

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So we have

$u_{s}mg=\frac{mv^2}{r}\\ u_{s}=\frac{v^2}{gr}\\ Where\\v=\frac{2\pi R}{T} \\So\\u_{s}=\frac{(\frac{2\pi R}{T} )^2}{gr} \\u_{s}=\frac{4\pi^2 r}{gT^2}$