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Korvikt [17]
3 years ago
15

Which two particles are present in the nucleus of an atom? Electrons and neutrons Electrons and molecules 1 TH O Protons and neu

trons O Protons and electrons​
Physics
1 answer:
aleksandrvk [35]3 years ago
8 0

Answer:

Protons and neutrons

Explanation:

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Physical science tries to a. Survey all of science b. Describe the environment and interaction between living things c. Describe
RideAnS [48]

Answer:

option "c" is correct

Explanation:

Physical science or Physics is the study of matter, energy and their mutual relationship.

7 0
3 years ago
A proposed space station includes living quarters in a circular ring 50.0 m in diameter. At what angular speed should the ring r
mel-nik [20]
Given that the space station is free of gravitational force, it is required that it spins an certain speed to acquire centripetal acceleration.

In this case, you want that the centripetal acceleration, Ac, equals g (gravitational acceleration on the earth), becasue this will cause a centripetal force equal to the weight on earth.

The formula for centripetal acceleration is Ac = [angular velocity]^2*R

where R = [1/2]50.0m = 25.0 m

Ac = 9.81 m/s^2

=> [angular velocity]^2 = Ac/R = 9.81m/s^2v/ 25.0m = 0.3924 (rad/s)^2

[angular velocity] = √(0.3924) rad/s = 0.63 rad/s

Answer: 0.63 rad/s

 

5 0
3 years ago
How much kinetic energy does a care 1000 kg car moving at 7 m/s have?
aalyn [17]
Hey there!

<span>How much kinetic energy does a care 1000 kg car moving at 7 m/s have?

Answer:
</span><span>A. 24500 J

Hope this helps
Have a great day (:
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5 0
3 years ago
A 45.0 kg student runs at a constant velocity up the incline 6 metres high. If the power output of the student is 1.50 x 103 W,
serg [7]

Answer:

The time taken is 1.76 s.

Explanation:

mass of student, m = 45 kg

height, h = 6 m

power, P = 1500 W

Power is defined as the rate of doing work.

Work done in moving height is

W = m g h

Let the time is t.

P = m g h / t

1500 = 45 x 9.8 x 6 / t

t = 1.76 s

3 0
3 years ago
Una caja de 40.0 kg se desliza 4.00 m hacia arriba por un plano inclinado de 26° con respecto a la acción de una fuerza de 340 N
otez555 [7]

Answer:

W = 320.30 J

Explanation:

To calculate the net work done over the block you take into account all implied forces:

\Sigma F=F+F_gsin\theta-F_fcos\theta  (1)

The gravitational force and friction force are against the applied force F.

θ = 26°

F: applied force = 340N

Fg: gravitational force = Mg = (40.0kg)(9.8m/s^2) = 392N

Ff: friction force = \mu N=\mu Mg=(0.250)(392N)=98N

Next, you replace to obtain the net force:

F_N=(340N)-(392N)sin(26\°)-(98N)cos(26\°)\\\\F_N=80.07N

Finally, the net work, for 4 m, is:

W_N=F_Nd=(80.07N)(4m)=320.30J

6 0
3 years ago
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