1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marysya12 [62]
3 years ago
9

Clinical thermomerter​

Chemistry
2 answers:
Yuki888 [10]3 years ago
6 0
A small medical thermometer with a short but finely calibrated range, for taking a person's temperature.
goldenfox [79]3 years ago
3 0

Answer:

Here is the definition: A medical thermometer (also called clinical thermometer) is used for measuring human or animal body temperature.

You might be interested in
With white light, a team measured a 0.7% percent change with 3.5g of plant matter in a one liter container. Convert
Strike441 [17]

moles CO₂ = 5.57.10⁻⁴

<h3>Further explanation   </h3>

A mole is a number of particles(atoms, molecules, ions)  in a substance

Can be formulated :

\tt mol=\dfrac{mass}{MW}

0.7% percent change with 3.5g of plant matter

mass :

\tt 0.7\%\times 3.5~g=0.0245~g

moles :

\tt moles=\dfrac{0.0245}{44}=0.000557=5.57.10^{-4}

5 0
3 years ago
How does increasing the temperature affect a reaction?
Luden [163]

Answer:A. An increase in temperature increases the reaction rate.

Explanation:because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction.

4 0
3 years ago
Please help me with my 8th grade chemistry, I'm really confused
saveliy_v [14]

Answer:

The answer would be C, in both chemical and physical change, because everything is made up of matter. So if you have a chemical or physical change, that doesent change the total mass of your product ever.

Explanation:

7 0
2 years ago
An unknown compound contains 38.7 % calcium, 19.9 % phosphorus and 41.2 % oxygen. what is the empirical formula of this compound
Temka [501]

The amount per 100 g is:

38.7 % calcium = 38.7g Ca / 100g compound = 38.7g

19.9 % phosphorus = 19.9g P / 100g compound = 19.9g

41.2 % oxygen = 41.2g O / 100g compound = 41.2g

The molar amounts of calcium, phosphorus and oxygen in 100g sample are calculated by dividing each element’s mass by its molar mass:

Ca = 38.7/40.078 = 0.96

P = 19.9/30.97 = 0.64

O = 41.2/15.99 = 2.57

C0efficients for the tentative empirical formula are derived by dividing each molar amount by the lesser value that is 0.64 and in this case, after that multiply wih 2.

Ca = 0.96 / 0.64 = 1.5=1.5 x 2 = 3

P = 0.64 / 0.64 = 1 = 1x2= 2

O = 2.57 / 0.64 = 4= 4x2= 8

Since, the resulting ratio is calcium 3, phosphorus 2 and oxygen 8

<span>So, the empirical formula of the compound is Ca</span>₃(PO₄)₂

5 0
3 years ago
Please help me :( Thank you so much ❤️
m_a_m_a [10]

Answer:

G- Gallons-Miles

Explanation

Even though gallons of gas are converted to miles you cannot physically convert gallons of something to miles.

6 0
3 years ago
Other questions:
  • An unknown element "x" can form a compound with the formula "x"br2. in which main group on the periodic table would element "x"
    15·1 answer
  • How many molecules are in 4.2 miles of water?​
    7·1 answer
  • What does frequency describe? A.distance from crest to crest or from trough to trough on a wave B.Number of waves that pass a gi
    7·1 answer
  • Para balancear una ecuacion quimica se cuenta el numero de:
    7·1 answer
  • Write the chemical equation for the reaction in which silver carbonate is formed
    11·1 answer
  • Need help on dis plz that would be big help
    9·2 answers
  • 20 <br> very very very very very very very very hard
    9·1 answer
  • Match the following scientist with his experiment or contribution
    9·1 answer
  • What is the mass of 3.2 L of water in centigrams?
    11·1 answer
  • All materials are made of _____________.
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!