Clinical thermomerter
2 answers:
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Answer:
1 gramo de metano aporta 50.125 kilojoules.
1 gramo de metano aporta 48.246 kilojoules.
Explanation:
La cantidad de energía liberada por la combustión de una unidad de masa del hidrocarburo (), en kilojoules por mol, es igual a la cantidad de energía liberada por mol de compuesto (
), en kilojoules por mol, dividido por su masa molar (
), en gramos por mol:
(1)
A continuación, analizamos cada caso:
Metano
1 gramo de metano aporta 50.125 kilojoules.
Octano
1 gramo de metano aporta 48.246 kilojoules.
Answer:
Explanation:
Hello,
In this case, it is widely known that for isochoric processes, the change in the enthalpy is computed by:
Whereas the change in the internal energy is computed by:
So we compute the initial and final temperatures for one mole of the ideal gas:
Next, the change in the internal energy, since the volume-constant specific heat could be assumed as ³/₂R:
Then, the volume-pressure product in Joules:
Finally, the change in the enthalpy for the process:
Best regards.