That process is called the Miranda rights
(B is the answer!!
I took the test and I got a 100! Hope this helps
Answer:
15,505 N
Explanation:
Using the principle of conservation of energy, the potential energy loss of the student equals the kinetic energy gain of the student
-ΔU = ΔK
-(U₂ - U₁) = K₂ - K₁ where U₁ = initial potential energy = mgh , U₂ = final potential energy = 0, K₁ = initial kinetic energy = 0 and K₂ = final kinetic energy = 1/2mv²
-(0 - mgh) = 1/2mv² - 0
mgh = 1/2mv² where m = mass of student = 70kg, h = height of platform = 1 m, g = acceleration due to gravity = 9.8 m/s² and v = final velocity of student as he hits the ground.
mgh = 1/2mv²
gh = 1/2v²
v² = 2gh
v = √(2gh)
v = √(2 × 9.8 m/s² × 1 m)
v = √(19.6 m²/s²)
v = 4.43 m/s
Upon impact on the ground and stopping, impulse I = Ft = m(v' - v) where F = force, t = time = 0.02 s, m =mass of student = 70 kg, v = initial velocity on impact = 4.43 m/s and v'= final velocity at stopping = 0 m/s
So Ft = m(v' - v)
F = m(v' - v)/t
substituting the values of the variables, we have
F = 70 kg(0 m/s - 4.43 m/s)/0.02 s
= 70 kg(- 4.43 m/s)/0.02 s
= -310.1 kgm/s ÷ 0.02 s
= -15,505 N
So, the force transmitted to her bones is 15,505 N
During the inflow part of a cycle in the neurons approximately 5.6 × 10∧11 Na ions per meter, each with a charge of +e enter the axon.
Therefore, ions will be (5.6 ×10∧11) × (1.2/100)
= 6.72 × 10 ∧8 Na ions
Charge of an electron is 1.6 × 10∧-19 Coulombs
Thus; 6.72 ×10∧ 8 ×1.6 ×10∧-19 = 1.0752 ×10∧-10 coulombs
To solve this problem it is necessary to apply the conservation equations of the moment for an inelastic impact or collision. In turn, it is necessary to apply the equations related to the conservation of potential energy and kinetic energy.
Mathematically this definition can be expressed as
Where,
Initial velocity of each object
Mass of each object
Final velocity
Our values are given as
Replacing we can find the value of the final velocity, that is
From the definition of the equations of simple harmonic motion the potential energy of compression and equilibrium must be subject to
Since there is no kinetic energy due to the zero speed in compression, nor potential energy at the time of equilibrium at the end, we will have to
Re-arrange to find A
Finally, the period can be calculated through the relationship between the spring constant and the total mass, that is,
