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4 years ago

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Two long parallel wires placed side-by-side on a horizontal table carry identical size currents in opposite directions. The wire

on your right carries current toward you, and the wire on your left carries current away from you. From your point of view, the magnetic field at the point exactly midway between the two wiresA) points away from you.B) is zero.C) points toward you.D) points down.E) points up.

1 answer:

N76 [4]4 years ago

6 0

Answer:

D) Points down

Explanation:

We can find the direction of the magnetic field produced by each of the wire by using the right hand rule:

- the thumb must correspond to the direction of the current in the wire

- the other fingers wrap around the thumb and gives the direction of the magnetic field lines

For the wire on the right, we have:

- thumb (current): towards you

- other fingers (magnetic field): at the left of the wire, they point down

For the wire on the left, we have:

- thumb (current): away from you

- other fingers (magnetic field): at the right of the wire, they point down

So, both magnetic fields point down at the point halfway between the two wires, so the net field is also pointing down.

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A drunken sailor stumbles 550 meters north, 500 meters northeast, then 450 meters northwest. What is the total displacement and

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Answer:

the magnitude of the average force on the bumper is 3189.8 N

Explanation:

Given the data in the question;

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W = $F^>$ × $x^>$

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where F is force applied, x is displacement and θ is angle between force and displacement.

Now, since the displacement of the bumper and force acting on it is in the same direction,

hence, θ = 0°

we substitute into equation 1

W = $Fxcos($ 0° $)$

W = $Fx$ ------- let this be equation 2

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$W_{net$ = ΔKE

= $\frac{1}{2}$ mv² - $\frac{1}{2}$ mu² --------- let this be equation 3

where m is mass of object, v is final velocity, u is initial velocity.

from equation 2 and 3

$Fx$ = $\frac{1}{2}$ mv² - $\frac{1}{2}$ mu²

we make F, the subject of formula

F = $\frac{m}{2x}$ ( v² - u² )

given that mass of car m = 830 kg, x = 0.255 m, v = 0 m/s, and u = 1.4 m/s

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F = $\frac{830}{(2)(0.255)}$ ( (0)² - (1.4)² )

F = 1627.45098 ( 0 - 1.96 )

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