Answer:
The total heat required is 691,026.36 J
Explanation:
Latent heat is the amount of heat that a body receives or gives to produce a phase change. It is calculated as: Q = m. L
Where Q: amount of heat, m: mass and L: latent heat
On the other hand, sensible heat is the amount of heat that a body can receive or give up due to a change in temperature. Its calculation is through the expression:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the change in temperature (Tfinal - Tinitial).
In this case, the total heat required is calculated as:
- Q for liquid water. This is, raise 248 g of liquid water from O to 100 Celsius. So you calculate the sensible heat of water from temperature 0 °C to 100° C
Q= c*m*ΔT
Q=103,763.2 J
- Q for phase change from liquid to steam. For this, you calculate the latent heat with the heat of vaporization being 40 and being 248 g = 13.78 moles (the molar mass of water being 18 g / mol, then
)
Q= m*L
Q=562.0862 kJ= 562,086.2 J (being 1 kJ=1,000 J)
- Q for temperature change from 100.0
∘
C to 154
∘
C, this is, the sensible heat of steam from 100 °C to 154°C.
Q= c*m*ΔT
Q=25,176.96 J
So, total heat= 103,763.2 J + 562,086.2 J + 25,176.96 J= 691,026.36 J
<u><em>The total heat required is 691,026.36 J</em></u>
<u>Answer:</u> The solubility of carbon dioxide at 5.50 atm is 
<u>Explanation:</u>
To calculate the molar solubility, we use the equation given by Henry's law, which is:
Or,
where,
are the initial concentration and partial pressure of carbon dioxide
are the final concentration and partial pressure of carbon dioxide
We are given:
Putting values in above equation, we get:
Hence, the solubility of carbon dioxide at 5.50 atm is
The true statements are B, C, and D
-first ( A ) the concentrations of reactants and products are equal is false, As the concentrations of reactants and products may be different from each other.
- But (B) the concentrations of reactants and product remains constant is true, as the equilibrium remains when there is no change in the concentration of the reactants and products.
-(c) reactants are being converted to products (and vise verse) is true also, as there are reactions still happened at a constant rate so it looks like nothing is happening.
Answer:
A. 2,3 BPG
Explanation:
2,3-bisphosphoglycerate (BPG), otherwise known as 2,3-DPG, enables the transition of hemoglobin from a very high-oxygen-affinity state to a reduced-oxygen-affinity state.
Tissues hemoglobin oxygen affinity is reduced by numerous physiological factors including.
1. Temperature Increased,
2. Carbon dioxide,
3. Acid and
4. 2,3-Bisphosphoglycerate (2,3-BPG)
all of which can contribute to decrease the oxygen affinity of hemoglobin which favours unloading and increased oxygen availability to our body cells.
Answer:
There is no chemical symbol for paper since it is not an element but rather a mixture of several different compounds. Mixtures in two or more phases are heterogeneous mixtures.
Explanation:
