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3 years ago

A basketball is filled with air and has a small hole. Explain why the basketball would leak.

2 answers:

7 0

The basket ball won't leak but the air would. the air will escape while it is being pressured by gravity, or when you bounce it. then the ball wouldn't work.

Assoli18 [71]3 years ago

4 0

Because it has a small hole and air is like water, an area of higher pressure wants to move to a lower pressure area.

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Show how the alternative definition of power, found in your book, can be derived by substituting the definitions of work and spe

Harman [31]

Let us consider body moves a distance S due to the force F.

Hence the work by the body W = FS

If the force is not along the direction of displacement,then the work by a body for travelling a distance S will be -

$W=[ Fcos\theta]*S$ where $Fcos\theta$ is the component of the force along the direction of displacement.

$Hence\ W= FScos\theta$

$= F.S$

As per the question the power P is given as -

$P=\frac{W}{\delta t}$

$=\frac{F.S}{\delta t}$

$= F.\frac{S}{\delta t}$

$= \ F.V$

Hence alternative definition of power P = F.V

8 0

3 years ago

Read 2 more answers

List things in your house and put them in order of density

ELEN [110]

I don't know what's in your house! lol. try naming things like: ball, lamp, cup, bowl.

3 0

3 years ago

Read 2 more answers

20 N effort is used in the 20 cm long spanner to unscrew a nut, then calculate momentum to unscrew the nut. [ Ans=4 Nm]

irga5000 [103]

Answer:

Refer to the attachment.

7 0

3 years ago

An unknown substance has a mass of 15 g and a volume of 4 cm3. Calculate the density of the unknown substance.

myrzilka [38]

Answer:

Density is 3.75g/cm3

Explanation:

Density = mass ÷ volume

= 15g ÷ 4cm3

= 3.75g/cm3

5 0

3 years ago

An open pipe of length 0.39m vibrates in the third harmonic with a frequency of 1400Hz. What is the distance from the center of

Gnoma [55]

Length of the pipe = 0.39 m

Third harmonic frequency = 1400 Hz

For the third harmonic:

Wavelength = $\frac{2L}{3}$

The center of the open pipe will host a node and the nearest anti - node from the center will be at the 0.25 × wavelength

Distance from center = 0.25 × wavelength

Distance = $0.25 x \frac{2L}{3}$

Plugging the value of the length of the pipe (L) = 0.39 m = 39 cm

Distance = $0.25 x \frac{2 \times 39}{3}$

Distance from the center to the nearest anti - node = 6.5 cm

Hence, the nearest distance to the anti - node from the center = 6.5 cm

So, option C is correct.

7 0

3 years ago