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2 years ago

9

Predict the missing component in the nuclear equation

1 answer:

Naddik [55]2 years ago

7 0

The answer is C since both charge and mass have to be balanced on both sides of the equation.

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What are the four energy sublevels electrons can be found in?

melomori [17]

The answer is B. s, p, d, f

3 0

3 years ago

If it takes 7,529 calories of heat to warm 750.0 grams of water, what was the temperature change? The specific heat of water in

Zigmanuir [339]

Answer:

The temperature change was 10.04 °C.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system. In this way, there is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case you know:

Q= 7,529 calories (cal)

c= 1 $\frac{cal}{g*C}$

M=750 grams

Replacing:

7,529 cal= 1 $\frac{cal}{g*C}$ *750 g* ΔT

Solving you get:

ΔT= $\frac{7,529 cal}{1 \frac{cal}{g*C}*750 g }$

ΔT= 10.04 °C

So, <u><em>the temperature change was 10.04 °C.</em></u>

6 0

3 years ago

Read 2 more answers

Boiling point elevation means that:

jeka94

Answer:

B. it will take more energy for the particles of the solution to overcome the atmospheric pressure.

Explanation:

i checked the slideshow from educere lol (slide 8 colligative properties lesson)

8 0

3 years ago

Based on the graphs below, which of the following substances has the highest specific heat capacity? Assume each experiment bega

ivann1987 [24]

It will not heat as fast with water

5 0

4 years ago

Consider the chemical equation for the ionization of CH3NH2 in water. Estimate the percent ionization of CH3NH2 in a 0.050 M CH3

anyanavicka [17]

Answer: The percent ionization of $CH_3NH_2$ in a 0.050 M $CH_3NH_2(aq)$ solution is 8.9 %

Explanation:

$CH_3NH_2+H_2O\rightarrow OH^-+CH_3NH_3^+$

cM 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_b=\frac{(c\alpha)^{2}}{c-c\alpha}$

Give c= concentration = 0.050 M and $\alpha$ = degree of ionisation = ?

$K_b=4.4\times 10^{-4}$

Putting in the values we get:

$4.4\times 10^{-4}=\frac{(0.050\times \alpha)^2}{(0.050-0.050\times \alpha)}$

$(\alpha)=0.089$

percent ionisation = $0.089\times 100=8.9\%$

8 0

3 years ago