How many minutes are in 3.5 years

Chemistry

1 answer:

-Dominant- [34]3 years ago

7 0

Answer: 1,839,600 minutes.

Explanation: 3.5 years to minutes has been calculated by multiplying 3.5 years by 525,600

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Assume that silver and gold form ideal, random mixtures. Calculate the mass of pure Ag needed to cause an entropy increase of 20

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Answer:

$m_{Ag}=2,265.9g$

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In this case, since the definition of entropy in a random mixture is:

$\Delta S=-n_TR\Sigma[x_i*ln(x_i)]$

For this silver-gold mixture we write:

$\Delta S=-(n_{Au}+n_{Ag})R\Sigma[\frac{n_{Au}}{n_{Au}+n_{Ag}} *ln(\frac{n_{Au}}{n_{Au}+n_{Ag}} )+\frac{n_{Ag}}{n_{Au}+n_{Ag}} *ln(\frac{n_{Ag}}{n_{Au}+n_{Ag}} )]$