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Alex73 [517]
3 years ago
15

Name 3 common acids that you use in your home

Chemistry
1 answer:
skad [1K]3 years ago
7 0

Answer:

vinegar, soft drinks, seltzer water , citrus fruits

Explanation:

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After creating a definition for what it means to be sexually abstinent, list reasons why being abstinent is important for you an
Sever21 [200]
Sexually abstinent: refraining from some or all sexual activities
school (higher education)
health (stds)
pregnancy (not ready for children)
5 0
3 years ago
In a titration of 47.41 mL of 0.3764 M ammonia with 0.3838 M aqueous nitric acid, what is the pH of the solution when 47.41 mL +
Volgvan

<u>Answer:</u> The pH of the solution is 1.136

<u>Explanation:</u>

To calculate the moles from molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

  • <u>For ammonia:</u>

Molarity of ammonia = 0.3764 M

Volume of ammonia = 47.41 mL = 0.04741 L   (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

0.3764mol/L=\frac{\text{Moles of ammonia}}{0.04741L}\\\\\text{Moles of ammonia}=0.01784mol

  • <u>For nitric acid:</u>

Molarity of nitric acid = 0.3838 M

Volume of ammonia = (47.41 + 10.00) mL = 57.41 mL= 0.05741 L

Putting values in above equation, we get:

0.3838mol/L=\frac{\text{Moles of nitric acid}}{0.05741L}\\\\\text{Moles of nitric acid}=0.02203mol

After the completion of reaction, amount of nitric acid remained = 0.022 - 0.0178 = 0.0042 mol

For the reaction of ammonia with nitric acid, the equation follows:

                       NH_3+HNO_3\rightarrow NH_4NO_3

At t=0             0.0178   0.022

Completion        0     0.0042        0.0178

As, the solution of the reaction is made from strong acid which is nitric acid and the conjugate acid of weak base which is ammonia. So, the pH of the reaction will be based totally on the concentration of nitric acid.

To calculate the pH of the reaction, we use the equation:

pH=-\log[H^+]

where,

[H^+]=\frac{0.0042mol}{0.05741L}=0.0731M

Putting values in above equation, we get:

pH=-\log(0.0731)\\\\pH=1.136

Hence, the pH of the solution is 1.136

8 0
3 years ago
How many moles of Cu(OH)2 will be produced if given 1 mole<br> KOH.
stiks02 [169]

Answer:

0.032 mole

Explanation:

Please mark me as brainliest

7 0
2 years ago
"What volume of" a 0.300 M BaF2 "solution is needed to prepare" 240.0 mL of a 0.100 M F- solution
zhannawk [14.2K]
Use M x V = M' x V'

0.300 x V = 0.100 x 250

V = .......... ml
6 0
4 years ago
Energy is transferred
Andrei [34K]
True is the right oneee
6 0
3 years ago
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