Answer:
If the force applied is larger than 185.2 N, yes.
Explanation:
In order to move the table, the pushing force must be larger than the frictional force. The frictional force is given by:

where
 is the coefficient of static friction
 is the coefficient of static friction
 is the mass of the table
 is the mass of the table
 is the gravitational acceleration
 is the gravitational acceleration
Substituting,

So, we are able to move the table if we push with a force larger than 185.2 N.
 
        
             
        
        
        
Its acceleration is 10ft/ sec
 
        
             
        
        
        
To solve this problem we will apply the definition of the ideal gas equation, where we will clear the density variable. In turn, the specific volume is the inverse of the density, so once the first term has been completed, we will simply proceed to divide it by 1. According to the definition of 1 atmosphere, this is equivalent in the English system to

The ideal gas equation said us that,
PV = nRT
Here,
P = pressure
V = Volume
R = Gas ideal constant 
T = Temperature 
n = Amount of substance (at this case the mass)
Then

The amount of substance per volume is the density, then

Replacing with our values,


Finally the specific volume would be


 
        
             
        
        
        
<span>Since forces are vector quantities, we must indicate direction using positive and negative values. East will be assigned positive and west will be negative. Friction will act as a negative force since it impedes action. To calculate the net force we sum the vector quantities, as follows. Net force equals 50n which is derived by the following calculation: 300n-220n-30n.</span>