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KIM [24]
1 year ago
8

HELP ASAP PLEASE!!!

Physics
1 answer:
tankabanditka [31]1 year ago
4 0

If resistor A, B and C are arranged in series, same current will flow in all the resistors and 2A will flow is resistor C.

<h3>What is series circuit?</h3>

This is the type of circuit arrangement in which the resistors are arranged in series order.

In this type of circuit arrangement, same current flows in every component of the circuit.

Thus, if resistor A, B and C are arranged in series, same current will flow in all the resistors and 2A will flow is resistor C.

Learn more about series circuit here: brainly.com/question/19865219

#SPJ1

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3 years ago
If the current through a 20-Ω resistor is 8.0 A , how much energy is dissipated by the resistor in 1.0 h ? Express your answer w
marshall27 [118]

Answer:

P(3600)=593.247W

Explanation:

First, let's find the voltage through the resistor using ohm's law:

V=IR=20*8=160V

AC power as function of time can be calculated as:

P(t)= V*I*cos(\phi)-V*I*cos(2 \omega t-\phi)  (1)

Where:

\phi=Phase\hspace{3}angle\\\omega= Angular\hspace{3}frequency

Because of the problem doesn't give us additional information, let's assume:

\phi=0\\\omega=2 \pi f=2*\pi *(60)=120\pi

Evaluating the equation (1) in t=3600 (Because 1h equal to 3600s):

P(3600)=160*8*cos(0)-160*8*cos(2*120\pi*3600-0)\\P(3600)=1280-1280*cos(2714336.053)\\P(3600)=1280-1280*0.5365255751\\P(3600)=1280-686.7527361=593.2472639\approx=593.247W

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3 years ago
A push of magnitude P acts on a box of weight W as shown in the figure. The push is directed at an angle θ below the horizontal,
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2 years ago
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T = 2π√(mL²/3 /mgL/2)

T = 2π√(2L/3g)

substituting the values of the variables into the equation, we have

T = 2π√(2L/3g)

T = 2π√(2 × 1.83 m/(3 × 9.8 m/s² ))

T = 2π√(3.66 m/(29.4 m/s² ))

T = 2π√(0.1245 s² ))

T = 2π(0.353 s)

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