Answer:
Explanation:
i really dont know im a 4th grader
A. how much work is done by friction as the sled moves
30.0 m along the hill
We use the formula:
friction work = -µmgdcosΘ
friction work = -0.100 * 90 kg * 9.8 m/s^2 * 30 m * cos 60
friction work = - 1,323 J
B. how much work is done by the rope on the sled in
this distance?
We use the formula:
rope work = -mgd(sinΘ - µcosΘ) <span>
</span>rope work = - 90 kg * 9.8 m/s^2
* 30 m (sin 60 – 0.100 * cos 60)
rope work = 21,592 J
C. what is the work done by the gravitational force on
the sled?
We use the formula:
gravity work = mgdsinΘ
gravity work = 90 kg * 9.8 m/s^2 * 30 m * sin 60
gravity work = 22,915 J
D. what is the total work done?
We add everything:
total work = - 1,323 J + 21,592 J + 22,915 J
<span>total work = 43,184 J</span>
Answer:
40 mph
Explanation:
Velocity is displacement over time. Displacement is the straight line distance between the starting point and ending point.
v = x / t
v = 320 mi / 8 hr
v = 40 mph
Answer:If a 5-kilogram mass is raised vertically 2 meters from the surface of the Earth, its gain in potential energy is approximately 1) 0 J 2) 10 J 3) 20 J 4) 100 J 43.
Explanation:
A water - H20 because you can touch it