Answer:
Keep on moving
Explanation:
Newton's first law states "that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force."
Answer:
v = 15.8 m/s
Explanation:
Let's analyze the situation a little, we have a compressed spring so it has an elastic energy that will become part kinetic energy and a potential part for the man to get out of the barrel, in addition there is a friction force that they perform work against the movement. So the variation of mechanical energy is equal to the work of the fictional force
= ΔEm = -Em₀
Let's write the mechanical energy at each point
Initial
Em₀ = Ke = ½ k x²
Final
= K + U = ½ m v² + mg y
Let's use Hooke's law to find compression
F = - k x
x = -F / k
x = 4400/1100
x = - 4 m
Let's write the energy equation
fr d = ½ m v² + mgy - ½ k x²
Let's clear the speed
v² = (fr d + ½ kx² - mg y) 2 / m
v² = (40 4.00 + ½ 1100 4² - 60.0 9.8 2.50) 2/60.0
v² = (160 + 8800 - 1470) / 30
v = √ (229.66)
v = 15.8 m/s
Answer:
(a) Energy will be 675 J
(B) charge will be 450 C
(C) Total number of particles will be
Explanation:
We have given that a flashlight uses 0.75 watts of power
So power P = 0.75 watt
Voltage is given as V = 1.5 volt
Time is given as t = 15 minutes
We know that 1 minute = 60 sec
So 15 minutes =
(A) We know that energy is given by
(b) We know that energy is also given by
So
Now we have given charge on each particle
So number of charge particle
Answer:
116 N
Explanation:
Missing question: (found on google)
<em>"What is the force of the pitcher's hand on the 0.145 kg ball during this acceleration phase?
</em>
<em>Express your answer with the appropriate units."</em>
Solution:
First of all, we need to calculate the acceleration of the ball, given by
where
v = 40 m/s is the final velocity
u = 0 is the initial velocity
is the duration of the acceleration phase
Substituting,
Now we can find the force exerted on the ball by using Newton's second law:
where
m = 0.145 kg is the mass of the ball
a is the acceleration
Substituting,
The area of a square is given by:
A = s²
A is the square's area
s is the length of one of the square's sides
Let us take the derivative of both sides of the equation with respect to time t in order to determine a formula for finding the rate of change of the square's area over time:
d[A]/dt = d[s²]/dt
The chain rule says to take the derivative of s² with respect to s then multiply the result by ds/dt
dA/dt = 2s(ds/dt)
A) Given values:
s = 14m
ds/dt = 3m/s
Plug in these values and solve for dA/dt:
dA/dt = 2(14)(3)
dA/dt = 84m²/s
B) Given values:
s = 25m
ds/dt = 3m/s
Plug in these values and solve for dA/dt:
dA/dt = 2(25)(3)
dA/dt = 150m²/s