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rosijanka [135]
3 years ago
6

What type of reaction is shown below? *

Physics
1 answer:
balu736 [363]3 years ago
5 0

Answer:

Decomposition

Explanation:

A reaction in which one compound breaks up into two or more compounds is called a decomposition reaction.

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Determine the speed of the 50-kg cylinder after it has descended a distance of 2 m, starting from rest. Gear A has a mass of 10
Naddika [18.5K]

This question is incomplete, the missing image is uploaded along this answer below.

Answer:

the speed of the 50-kg cylinder after it has descended is 3.67 m/s

Explanation:

 Given the data in the question and the image below;

relation between velocity of cylinder and velocity of the drum is;

V_D = ω_c × r_c  ----- let this be equ 1

where V_D is velocity of cylinder,  ω_c is the angular velocity of drum C and r_c is the radius of drum C

Now, Angular velocity of gear B is;

ω_B = ω_C

ω_B = V_D / r_c  -------- let this equ 2

so;

V_D / 0.1 m = 10V_D

Next, we determine the angular velocity of gear A;

from the diagram;

ω_A( 0.15 m ) = ω_B( 0.2 m )

from equation 2; ω_B = V_D / r_c

so

ω_A( 0.15 m ) = (V_D / r_c ) 0.2 m

substitutive in value of radius r_c (0.1 m)

ω_A( 0.15 m ) = (V_D / 0.1 m ) 0.2 m

ω_A( 0.15 ) = 0.2V_D / 0.1

ω_A =  2V_D  / 0.15

ω_A = 13.333V_D   ----- let this be equation 3

To get the speed of the cylinder, we use energy conversation;

assuming that the final position is;

T₁ + ∑U_{1-2 = T₂

0 + m_Dgh = \frac{1}{2}m_DV²_D + \frac{1}{2}I_Aω²_A + \frac{1}{2}I_Bω²_B

so

m_Dgh = \frac{1}{2}m_DV²_D + \frac{1}{2}(m_Ak_A²)(13.333V_D)² + \frac{1}{2}(m_Bk_B²)(10V_D)²

we given that; m_D = 50 kg, h = 2 m, m_A = 10 kg, k_A 125 mm = 0.125 m, m_B = 30 kg, k_B = 150 mm = 0.15 m.

we know that; g = 9.81 m/s²

so we substitute

50 × 9.81 × 2 = ( \frac{1}{2} × 50 × V_D²) + \frac{1}{2}( 10 × (0.125)² )(13.333V_D)² + \frac{1}{2}( 30 × (0.15)²)(10V_D)²

981 = 25V_D² + 13.888V_D² + 33.75V_D²

981 = 72.638V_D²

V_D² = 981 / 72.638

V_D² = 13.5053

V_D = √13.5053

V_D = 3.674955 ≈ 3.67 m/s

Therefore,  the speed of the 50-kg cylinder after it has descended is 3.67 m/s

7 0
3 years ago
What is the relationship between wavelength of light and the quantity of energy per photon?
slamgirl [31]

Answer:

The quantity of energy per photon is inversely proportional to the wavelength of the light.

Explanation:

Energy of light is given as

E = hf

where E = energy of the photons,

f = frequency of the light

If the number of photons = n

(E/n) = (h/n) f

Let (E/n) = E'

(h/n) = h'

But the frequency of light is related to wavelength through the relation

v = fλ

where v = speed of light = c

λ = wavelength of light

f = (c/λ)

E' = h' f

Substituting for f

E' = h' (c/λ)

h' and c are both constants, h'×c = K

E' = (K/λ)

So, the quantity of energy per photon is inversely proportional to the wavelength of the light.

Hope this Helps!!!

3 0
3 years ago
Read 2 more answers
A car goes North a distance of 120 kilometers during a time period of 3.0 hours. What is the average
DIA [1.3K]

Answer:

the average speed of the car during this time interval is 40 m/s i thinkk..

8 0
3 years ago
a steel block has a mass of 40g.it is in the form of a cube. each edge is 1.74cm long. calculate the density
Vinil7 [7]

Answer:

d ≈ 7,6 g/cm³  

Explanation:

d = m/V = 40g/5,27cm³ ≈ 7,6 g/cm³

V = l³ = (1.74cm)³ ≈ 5,27 cm³

3 0
3 years ago
Jonathan is studying solutions in his chemistry class. The teacher instructs the students to measure 2 tablespoons of salt into
bulgar [2K]
8 tablespoons of water.
2 x 4 = 8

I hope this helps :)
3 0
2 years ago
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