The capacitance of a capacitor of a parallel plate is given by:

Where:

We also know:

As we can see the voltage halves
And since:

We can conclude that electric field and also the energy halve
Answer:

Explanation:
The electric force on a charged particle is given by

where
q is the charge of the particle
E is the strength of the electric field
In this problem, we have
is the electric field strength
is the charge of the calcium ion
Therefore, the electric force exerted on the calcium ion is

Answer:
filament bulb, filament lamp
Explanation:
Answer:
From 0 -4 seconds the acceleration is positive. (The graph is going upwards.)
From 6-10 seconds the acceleration is negative. (The graph is going downwards.)
Answer:
The initial current, Io = 2.06×10^-4A
Explanation:
The I itial current ,Io of a circuit is given by:
Io = Vo/R
Where Vo = initial votage
R = resistance in ohms
Given:
Vo = 1.50V
R = 7290ohms
Io = 1.50/ 7290
Io = 2.06 ×10^-4A